[(-3)+9] × [(-10)-(-9)]
6 × (-10 + 9)
6 × (-1)
= -6
A=PIEr^2, letting r=14
a=PIE(14)^2
=615.75ft^2
use the symbol pie as the substitution for the actual word
I am thinking as wisely as I can. I believe that Rachel would have jogged 2 miles, if you think about it. If 1/4 of the trail is jogged each time, and she does that 8 times, 1/4 + 1/4 + 1/4 + 1/4 +1/4 + 1/4 + 1/4 + 1/4= 8/4 or 2. I hope this helped!
Answer:
Robbin's grade point average must be at least 2.75 in order to be unconditionally accepted into the program.
Step-by-step explanation:
An unconditional acceptance into a graduate program at a university will be given to students whose GMAT score plus 100 times the undergraduate grade point average is at least 1075
Considering the GMAT score x, and the GPA y, this situation is modeled by the following inequality:

Robbin's GMAT score was 800.
This means that
, and thus:



What must her grade point average be in order to be unconditionally accepted into the program?
Solving the above inequality for y:



Thus:
Robbin's grade point average must be at least 2.75 in order to be unconditionally accepted into the program.
Answer:
im in online school
Step-by-step explanation: