Answer:
16 x 3? I'm not sure I understand sorry.
Answer:
No
Step-by-step explanation:
It depends on the shape of the stage, generally, the stage is cuboidal or cubical in shape, so assuming the stage is cuboidal.
Here, the spotlight has top cover the minimum angle of 90° (for a corner position of the spotlight.
Now, compute how much angles the spotlight can cover.
From its central position, the spotlight can rotate 25° to the left or right, so, angle covered due to rotation is 25°+25°=50°.
As the beam of light from the spotlight can spread 22°.
So, the total angle covered by spotlight= 50° + 22°=72°, which is less than the minimum angle required to cover the entire stage.
Hence, the designer can't use the spotlight to light each of the objects on the stage.
Answer:
64,98*63.98
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
So, there will be 40 green cars. if we want the ratio to be 1:3, we will need there to b three times as many silver cars as green cars: 40*3=120.
we already have 20 silver, so we need to add 120-20, that is 100 silver cars!
