Find the length of the side of an equilateral triangle whose area is 9√3 cm2

Simplify the expression. (4a- 80 - 4a2) + (7a3 - 7 - 6a)

allsm [11]

Answer:

the answer should be 7a^3-4a^2-2a-87

3 0

3 years ago

The digit \greenD88start color #1fab54, 8, end color #1fab54 in which number represents a value of 888 thousandths?

Arte-miy333 [17]

Question:

The digit 8 in which number represents a value of 8 thousandths?

Answer:

See Explanation

Step-by-step explanation:

The question requires options and the options are missing.

However, the following explanation will guide you

Start by representing 8 thousandths as a digit

$\frac{8}{1000} = 0.008$

i.e.

8 thousandths implies 0.008

Next;

Replace the 0s with dashes

_ . _ _8

Note that there are two dashes after the decimal point and before 8

PS: The dashes are used to represent digits

This implies that thousandths is the 3rd digit after the decimal point

Typical examples to back up this explanation are:

17.008, 1.1489, 0.008 and so on...

3 0

3 years ago

A single little brown bat can eat up to 1,000 mosquitoes in a single hour. Express in scientific notation how many mosquitoes a

Nastasia [14]

Our final answer must represent "number of mosquitos." This verifies that the correct calculation would be

1000 mosquitos 10.5 hours
----------------------- x --------------------
1 hour 1

Multiply this out. Note that "hours" will cancel.

Whats your result?

Supposing that your result looked like xxxxx times 10^0,

you'd convert this into scientific notation by moving the decimal place four units to the left (obtaining x.xxx) and then increasing the exponent of 10 from zero to four (obtaining 10^4).

Then your answer would have the form x.xxx times 10^4 (mosquitos)

8 0

3 years ago

What does 72 divided by 9 + 4x4 equal

MrMuchimi

72 divided by 9 = 8
8 + 4x4 = 8+16
8+16=24

5 0

3 years ago

Read 2 more answers

A nationwide study of American homeowners revealed that 65% have one or more lawn mowers. A lawnequipment manufacturer, located

GenaCL600 [577]

Answer:

$z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589$

$p_v =P(z>1.589)=0.056$

If we compare the p value obtained with the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

Step-by-step explanation:

Data given and notation

n=497 represent the random sample taken

X=340 represent the homes in Omaha with one or more lawn mowers

$\hat p=\frac{340}{497}=0.684$ estimated proportion of homes in Omaha with one or more lawn mowers

$p_o=0.65$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the true proportion of homes in Omaha with one or more lawn mowers is higher than 0.65.:

Null hypothesis: $p\leq 0.65$

Alternative hypothesis: $p > 0.65$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.684 -0.65}{\sqrt{\frac{0.65(1-0.65)}{497}}}=1.589$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>1.589)=0.056$

If we compare the p value obtained with the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of homes in Omaha with one or more lawn mowers is not ignificantly higher than 0.65

7 0

3 years ago