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dusya [7]
3 years ago
7

How do u solve 3= t + 11.5 - t ?

Mathematics
1 answer:
shepuryov [24]3 years ago
7 0

11.5

itssssssssssssssssssssssssssssssssssssssssssssssss



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Acellus. please help me
Doss [256]

by-step explaAnswer:

by-step epla

Step-nation:

a

6 0
3 years ago
Write a cosine function that has a midline of 2, an amplitude of 4 and a period of 4/7
ella [17]

Answer:

y= 4cos(\frac{7\pi }{2}x)+2

Step-by-step explanation:

We know that the transformations of a cosine equation can be shown as:

y=±a(b(x-h))+k

Where 'a' is the amplitude

'b' is the horizontal change (Do 2π/b to find the period)

'h' is the horizontal shift

and 'k' is the vertical shift or midline.

------------------------------------------------------

If the amplitude is 4, we can assume a=4.

Since the period is 4/7, we can solve for the 'b' value by:

2\pi /\frac{4}{7}= \frac{7\pi }{2}

Next, since the midline is 2, we know that a vertical shift of 2 occurred. Thus, the 'k' value is 2.

Writing this equation gives us:

y= 4cos(\frac{7\pi }{2}x)+2

4 0
4 years ago
Which expression means the sum of 5 and a number? A. g × 5 B. g – 5 C. g + 5 D. g ÷ 5
wel
For this case, the first thing you should do is define a variable.
 We have then:
 g: unknown number.
 We now write the expression in algebraic form.
 the sum of 5 and a number:
 g + 5
 Answer:
 
An expression that means the sum of 5 and a number is:
 
C. g + 5
5 0
3 years ago
Five thousand dollars is deposited into a savings account at 2.5% interest compounded continuously.
Mumz [18]

Answer:

A). A(t) = P(1+r/n)^(nt)

B). DA/Dt = np(1+r/n)^(t)

C). A(5) =$ 5664.0

D).t = approximately 13.5 years

Step-by-step explanation:

A(t) = P(1+r/n)^(nt)

P = $5000

n= t

r= 2.5%

After five years t = 5

A(t) = P(1+r/n)^(nt)

A(5) = 5000(1+0.025/5)^(5*5)

A(5) = 5000(1+0.005)^(25)

A(5)= 5000(1.005)^(25)

A(5) = 5000(1.132795575)

A(5) = 5663.977875

A(5) =$ 5664.0

When the balance A= $7000

A(t) = P(1+r/n)^(nt)

7000= 5000(1+0.025/n)^(nt)

But n= t

7000= 5000(1+0.025/t)^(t²)

7000/5000= (1+0.025/t)^(t²)

1.4= (1+0.025/t)^(t²)

Using trial and error

t = approximately 13.5 years

8 0
3 years ago
75% of all undergraduates are in the College, 10% are in Engineering, 8% are in Commerce, 4% are in Nursing, and 3% are in Archi
Hunter-Best [27]

Answer:

the probability a randomly selected student is a third-year that they are in the College is 0.1743

Step-by-step explanation:

Given information

75% College = C = 0.75

10% are in Engineering, Eng = 0.1

8% are in Commerce, Com = 0.08

4% are in Nursing, Nurs = 0.04

3% are in Architecture, Arch = 0.03

21% Third year student = S = 0.21

21% in the College = 0.21

25% in Engineering = 0.25

49% in Commerce = 0.49

57% in Nursing = 0.57

33% in Architecture = 0.33

P(SlC) = 0.75 x 0.21 = 0.1575 is the probability of third year student in college

P(SlEng) = 0.1 x 0.25 = 0.025

P(SlCom) = 0.08 x 0.49 = 0.0392

P(SlNurs) = 0.04 x 0.57 = 0.0288

P(SlArch) = 0.03 x 0.33 = 0.0099

P(S) = P(SlEng) + P(SlCom) + P(SlNurs) +P(SlArch)

       = 1- (0.025 + 0.0392 + 0.0288 + 0.0099)

       = 0.9031

The probability of third year student in college is

P(ClS) = P(SlC) / P(S)

           = 0.1575 / 0.9031

           = 0.1743

3 0
4 years ago
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