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2 years ago

How do u solve 3= t + 11.5 - t ?

Mathematics

1 answer:

shepuryov [24]2 years ago

7 0

11.5

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Graph this equation y=3sin(2x-5)

OLEGan [10]

Y = 3sin(2x - 5)
y = 3sin(2x - 5)

6 0

2 years ago

-9 + 10 over 4 equals negative 7

umka21 [38]

-9 + 10 over 4 = -7

1/4 = -7

1/4 does not equal -7

7 0

2 years ago

How do you do this Problem using factoring (fx)=4x^2-25?

Yanka [14]

Answer: (2x+5)(2x−5)

Step-by-step explanation:For me, what i like to do is to try divide the problem into two parts. For example in this problem, you would divide the 4x^2 into two 4x(since 4x+4x = 4x^2). Then 25 can be divide into into 5s (5x5=25). SInce you know that its a negative 25, you know that it has to be a negative on one of the sides. So the answer in factor form is (2x+5)(2x−5)

5 0

3 years ago

I need help with this problem

Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒ $cosA=\frac{u.v}{|u||v|}$

Given u=-8i-3j and v=-8i+8j

$|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544$

$|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137$

let A be angle before u and v

therefore, $cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}$

⇒ $A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56$

Therefore angle between u and v is 65.56°

5 0

2 years ago

Can someone help me? Files attached! <br> What answer choices go to what figure? :D

den301095 [7]

Since the center is considered the corner that they both share, here are the answers figure a goes with the first, figure b goes with the last, figure c goes with the second, and figure d goes with the third. Hope this helps.

3 0

3 years ago