3 years ago

(X^-4)(x^10)=x^p Help:(

Mathematics

1 answer:

kkurt [141]3 years ago

6 0

Answer:

Step-by-step explanation:

$(x^{-4})*(x^{10})=x^{p}\\\\x^{-4+10}=x^{p}\\\\x^{6}=x^{p}\\$

Compare the powers, p = 6

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Help question attached multiple choice

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ANSWER

$x = \frac{\pi}{2} , \frac{7\pi}{6} , \frac{3\pi}{2} , \frac{11\pi}{6}$

EXPLANATION

The given trigonometric equation is

$\cos(x) + 2 \cos(x) \sin(x) = 0$

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$\cos(x) (1 + 2 \sin(x) ) = 0$

Apply the zero product property to obtain:

$\cos(x) = 0 \: or \: 1 + 2 \sin(x) = 0$

$\cos(x) = 0 \: or \: \sin(x) = - \frac{1}{2}$

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We know

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The sine function is negative in the third and fourth quadrants.

$x = \pi + \frac{\pi}{6} = \frac{7\pi}{6}$

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3 years ago