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valentinak56 [21]
3 years ago
13

a student studies the same amount of time each day for a test in 4 days she studied 60 minutes which equation shows this relatio

nship let x = the number of days
Mathematics
1 answer:
Keith_Richards [23]3 years ago
8 0
Y=mx
m=amount of time per day studied
y=time
x=number of days
we have
60=m(4)
divide by 4
15=m

y=15x

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The midpoint of AB is (3,2). If point is is located at(8,4) what are the coordinates of point B
Dmitry [639]

Step-by-step explanation:

8-3 = 5,

3-5 = -2 = the x coordinate of B

-2-4 =-6,

-2-6 =-8 = the y coordinate of B

(-2,-8) is the point B

A is 5 to the right of the midpoint, so B is 5 to the left of the midpoint

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A van and a truck both drove from Town A to Town B. The distance
Gala2k [10]
First we need to find out the time it took for the truck to reach town B.

Speed= \frac{Distance}{Time}

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4 0
3 years ago
2 people working at the same rate will take 6 hours to paint a room.
zavuch27 [327]

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7 0
3 years ago
How many numbers between 50 and 500 are divisible by 7?​
weqwewe [10]

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3 years ago
Read 2 more answers
Suppose the mean SAT verbal score is 525 with a standard deviation of 100, while the mean SAT math score is 575 with a standard
Ipatiy [6.2K]

Answer:

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

Step-by-step explanation:

Normal variables

Normal variables have mean \mu and standard deviation \sigma

When we add normal variables, the combined mean is the sum of both means, and the standard deviation is the square root of the sum of both variances. The distribution is still normal.

In this question:

Verbal: \mu_{V} = 525, \sigma_{V} = 100.

Math: \mu_{M} = 575, \sigma_{M} = 100

Combined:

\mu = \mu_{V} + \mu_{M} = 525 + 575 = 1100

\sigma = \sqrt{\sigma_{V}^{2}+\sigma_{M}^{2}} = \sqrt{100^2 + 100^2} = 141

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

6 0
3 years ago
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