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2 years ago

Subtract 5/12 - 3/4 A.) 1/4 B.) 1 1/6 C.) -1/3 D. 1/3

Mathematics

2 answers:

raketka [301]2 years ago

7 0

Answer:

3/4 becomes 9/12

5-9 is -4 》-4/12 = -1/3 a.k.a C

pashok25 [27]2 years ago

6 0

Answer:

-1/3

Step-by-step explanation:

found the lowest common factor for the denominators of the fractions (5/12 and 3/4)

5/12 -3/4 = (5-9)/12

= -4/12

-1/3

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marta [7]

Step-by-step explanation:

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2 years ago

Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29

hram777 [196]

Answer:

$\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }$

Step-by-step explanation:

Hello,

I assume that we are working in $\mathbb{C}$ , otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

$p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0$

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

$p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b$

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

$\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }$

Now, we need to find the zeroes of the second factor, meaning finding x so that:

$x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4} \\ \\ x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\ x = 2+5i \ \text{ or } \ x = 2-5i$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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3 years ago

Help me with this, Its in the doc below

zvonat [6]

Answer:

https://faq.brainly.com/hc/en-us/articles/360014661139.

Step-by-step explanation:

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2 years ago

Evaluate 5c+cd when c=1/5 and d=15

oee [108]

5*1/5+1/5*15=4
1 + 3 =4

This should equal 4 if I did this correctly.

4 0

3 years ago

If f(x) = x^4-x^3+x^2 and g(x)= -x^2, where x does not = 0, what is (f/g)(x)?

Korvikt [17]

For this case we have the following functions:

$f (x) = x ^ 4-x ^ 3 x ^ 2\\g (x) = - x ^ 2$

By definition of composition of functions we have to: $(f \ g) (x) = \frac {f (x)} {g (x)}$

So:

$\frac {f (x)} {g (x)} = \frac {x ^ 4-x ^ 3 x ^ 2} {- x ^ 2} = \frac {x ^ 4} {- x ^ 2} +\frac {-x ^ 3} {- x ^ 2}+ \frac {x ^ 2} {- x ^ 2} =$

By definition of division of powers of the same base we have to place the same base and subtract the exponents:

$\frac {f (x)} {g (x)} = - x ^ 2+x-1$

ANswer:

$(\frac {f} {g}) (x) = - x ^ 2 +x-1$

3 0

3 years ago