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Zarrin [17]
2 years ago
6

I NEED HELP URGENTLY

Mathematics
1 answer:
tigry1 [53]2 years ago
5 0

Answer:

30 square millimeters

Step-by-step explanation:

3 x 3 = 9

3 x 1 = 3

there are two sides with the area 9 therefore...

9 x 2 = 18

There are four sides with the area 3 therefore...

3 x 4 = 12

Therefore the suface area is

12 + 18 = 30

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Hello everyone can you help me with this problem? Please
tekilochka [14]

Answer:

a=10.5

Step-by-step explanation:

2.25(a+1.3)=20.7\\2.25a+2.925=20.7\\-2.925\\2.25a=23.625\\

÷2.25

a=10.5

4 0
3 years ago
Find the limit (enter 'DNE' if the limit does not exist)
vaieri [72.5K]

Answer:

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{-2x^2-6y^2+1}+1\right)=2

Step-by-step explanation:

We need to first simplify the expression using rationalization(i.e. if a square root term exists in the denominator, then multiply and divide the whole expression by the denominator(but the change the sign of its middle term))

here, we need to find:

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\dfrac{-2x^2-6y^2}{\sqrt{-2x^2-6y^2+1}-1}\right)

first we'll rationalize our expression:

\dfrac{-2x^2-6y^2}{\sqrt{-2x^2-6y^2+1}-1}\left(\dfrac{\sqrt{-2x^2-6y^2+1}+1}{\sqrt{-2x^2-6y^2+1}+1}\right)

\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{(\sqrt{-2x^2-6y^2+1}+1)^2-(1)^2}

\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{-2x^2-6y^2+1-1}

\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{-(2x^2+6y^2)}

\sqrt{-2x^2-6y^2+1}+1

this is our simplified expression, now we can apply our limits:

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{-2x^2-6y^2+1}+1\right)

\sqrt{-2(0)^2-6(0)^2+1}+1

1+1

2

the limit does exists and it is 2.

5 0
3 years ago
A triangular fence is being built to surround a garden. If two of the side lengths must be 4 feet and 12 feet, which inequality
babymother [125]
The third side cannot be 16 or greater than 16.
also it must be greater than 8  ( because 4+8 = 12 = the other sde)

The answer is B   8 < x < 16
5 0
3 years ago
Please help!!!!!!!!!!!!!!
xeze [42]

Answer:

Step-by-step explanation:

7 0
3 years ago
What does it mean to evaluate an expression in 5th grade
MrRa [10]

Answer:

Usually it means to solve it. Sometimes they give you values to substitute in for variables (letters) in the math sentence/equation/expression.

Does that make sense?

Step-by-step explanation:

3 0
3 years ago
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