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3 years ago

What is the standard form of (4,4), perpendicular to y = -4/9x

Mathematics

1 answer:

Rudik [331]3 years ago

8 0

Y=9/4x-5 is the standard form.

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8/9 + 4/7 =<br> Can you get the Anwar for this sum

attashe74 [19]

here. I don't know if its right but i hope it is.

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3 years ago

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Is 312mg greater than 312dg

adelina 88 [10]

312 mg is not greater than 312 dg

5 0

3 years ago

Help me answer this and explain it please! :)

Fynjy0 [20]

Answer:

90. 04987916

Step-by-step explanation:

Let HI be a

and GH be c

and GI be b

and <GHI be B

Using the law of Cosines,

b^2= -2ac cos (B) + c^2 + a^2

= -2(42)(60) cos (123)+60^2+42^2

= -5040 cos (123) +3600+1764

= -5040(-0. 544639035) +5364

= 2744. 980736+5364

b^2= 8108. 980736

b= Sqrt ( 8108. 980736)

b= 90. 04987916

7 0

3 years ago

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The points with coordinates (x, -1), (2,2), and (4,3) lie on the same line. What is the value of x?

borishaifa [10]

Find the slope of the line passing throught the points (2, 2) and (4, 3).

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Substitute:

$m=\dfrac{3-2}{4-2}=\dfrac{1}{2}$

If the point (x, -1) lie on the same line, then the slope of line passing through the points (2, 2) and (x, -1) the same:

Substitute:

$m=\dfrac{-1-2}{x-2}=\dfrac{-3}{x-2}$

We have the equation:

$\dfrac{-3}{x-2}=\dfrac{1}{2}$ <em>cross multiply</em>

$(1)(x-2)=(-3)(2)$

$x-2=-6$ <em>add 2 to both sides</em>

$x=-4$

<h3>Answer: x = -4.</h3>

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3 years ago

I need the answer for this problem please

Savatey [412]

Answer:

Step-by-step explanation:

Find all probabilities:

A. False

$Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}$

B. True

$Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}$

C. False

$Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}$

D. False

$Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}$

4 0

3 years ago