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igor_vitrenko [27]
3 years ago
13

What is the standard form of (4,4), perpendicular to y = -4/9x

Mathematics
1 answer:
Rudik [331]3 years ago
8 0
Y=9/4x-5 is the standard form.
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Steps to scientific notation
chubhunter [2.5K]
1.Move the decimal place to the left to create a new number from 1 up to 10.
2.Determine the exponent, which is the number of times you moved the decimal.
3.Put the number in the correct form for scientific notation
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3 years ago
Find an expression which represents the difference when (-5x-y) is subtracted from (9x+2y) in simplest terms.
AnnyKZ [126]

Answer:

4x+y add like terms ... -5+9=4 and  -y(or -1)+2y=y

4 0
2 years ago
L1 : (3, 5) and (2,5) L2: (2, 4) and (0, 4) A. Perpendicular B. Parallel C. Neither
Tresset [83]

answer for this question is (b)parallel

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7Ba%2Bb%7D%20%7D%7B%5Csqrt%7Ba-b%7D%20%7D%20%2B%5Cfrac%7B%5Csqrt%7Ba-b%7D%20
andrezito [222]

Answer:

\frac{(a+b)}{a^{2} -b^{2}  } + \frac{(a-b)}{a^{2} -b^{2}  } = \frac{2a}{a^{2} -b^{2}  }

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A small combination lock on a suitcase has 4 ​wheels, each labeled with the 10 digits 0 to 9. how many 4 digit combinations are
tamaranim1 [39]
This is the easiest way to solve this problem:

Imagine this represents how many combinations you can have for each of the 4 wheels (each blank spot for one wheel): __ __ __ __

For the first situation it says how many combos can we make if no digits are repeated.
We have 10 digits to use for the first wheel so put a 10 in the first slot 
10 __ __ __
Since no digit can be repeated we only have 9 options for the second slot
10 9_ __ __
Same for the third slot, so only 8 options
<u>10</u> <u> 9 </u> <u> 8 </u> __
4th can't be repeated so only 7 options left
<u>10</u> <u> 9 </u> <u> 8 </u> <u> 7 
</u><u>
</u>Multiply the four numbers together: 10*9*8*7 = 5040 combinations


For the next two do the same process as the one above.

If digits can be repeated? You have ten options for every wheel so it would look like this: <u>10</u> <u>10</u> <u>10</u> <u>10
</u>
10*10*10*10 = 10,000 combinations

If successive digits bust be different?
We have 10 for the first wheel, but second wheel only has 9 options because 2nd number can't be same as first. The third and fourth wheels also has 9 options for the same reason.

<u>10</u> <u> 9</u><u> </u> <u> 9 </u> <u> 9 </u>

10*9*9*9 = 7290 combinations






8 0
2 years ago
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