Answer:
AC = 8 cm,
AD = 3 cm and ∠ACB = ∠CDA
From figure,
∠CDA = 90°
∴ ∠ACB = ∠CDA = 90°
In right angled ∆ADC,
AC2 = AD2 + CD2
⇒ (8)2 = (3)2 + (CD)2
CD2 = 64 – 9 = 55
⇒ CD = √55 cm
In ∆CDB and ADC.
∠BDC = ∠AD [each 90°]
∠DBC = ∠DCA [each equal to 90°-∠A]
∴ ∠CDB ∼ ∆ADC
Then,
Answer:
16cm
Step-by-step explanation:
Let the breadth = x
The length exceeds = x + 7
The breadth increased = x + 3
Because it said the length decreased by 4 so, the length would be:
x + 7 - 4 = x + 3
Original area:
We learn that:
area = length * breadth
x*(x+7) = (x+3)*(x+3)
x^2 + 7x = (x+3)^2
x^2 + 7x = x^2 + 6x + 9 (We also learn that (a+b)^2 = a^2 + 2ab + b^2
x^2 - x^2 + 7x - 6x = 9
x = 9 (so the breadth = 9)
The length = x + 7 = 9+7 = 16(cm)
Hope this help you :3
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Quadrant I
Answers. Sample Response: If (−2, −8) is reflected across both axes, it will be located at (2, 8), which is in Quadrant I. When a point is reflected across both axes, the signs of both the x- and y-coordinates change.
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sorry cant help u
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im bad at this