Hi,
-5x = -115
-115/-5 = 23
-5 × 23 = -115
The answer is 23
Hope this helps! :)
65 degrees. alternate exterior angles of two parallel lines intersected by a transversal are equal
The slope of the function for rise/run would be 3/2, this is because;
The function passes through (-5,1) and (1,10). Lets find the change on the y and x axis.
For the x axis;
-5 to 1.
That is a change of positive 6.
-5+6=1
For the y axis;
1 to 10.
That is a change of positive 9.
1+9=10
For the slope we must put rise (change in y axis) over run (change in x axis) to get 3/2 when simplified from 9/6.
For every 2 units of rise in the x axis the y axis rises by 3.
When two parallel lines are intersected by a transversal, the same-side exterior angles are supplementary. That means that their sum is 180.
Using that logic, if the two roads were parallel, then the sum of their same-side exterior angles will add up to 180. Yet their same-side exterior angles add up to 170 (130 + 40 = 170), hence they can't be parallel.
See the drawing attached below.
Using supplmenatry angles (two angles whose sum of measures add up to 180 or a straight line), we can say that:
m<DIE + m<HID = 18
40 + m<HID = 180
m<HID = 140
Similarly:
m<BHC + m<CHI = 180
130 + m<CHI = 180
m<CHI = 50
Using verticle angles therome, (when two lines intersect, the angles opposite to eachother are congruent, or have the same measure), we can say that:
m<DIE = m<GIH = 40
m<GIE = m<HID = 140
m<CHI = m<AHB = 50
m<BHC = m<AHI = 130
Answer:
A
Step-by-step explanation:
If you convert the first equation to y=mx+b form, it will be the same as the second equation.
6x - 15y = 15
-15y = -6x + 15
y =
x -1
Because the 2 equations are the same now, they are the same line.