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omeli [17]
3 years ago
13

(2x + 4) — (-x + 5) PLEASE HELP

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
6 0
(2x + 4) - (-x + 5)
= (2x + 4) -1(-x + 5)
= 2x + 4 + x - 5
= 2x + x + 4 - 5
= 3x - 1.
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Consider a circle centered at C(-2,-4). If the point P(1,-1) lies on the circle, then which of the following points also lies on
Aliun [14]

Answer:

Consider a circle centered at C(-2,-4). If the point P(1,-1) lies on the circle, then which of the following points also lies on the circle?

<h3>A. (-2, -√18)</h3>

B. (-2+√18, -4)

C. (√18, -4)

D. (-2, 4+√18)

Step-by-step explanation:

  • If the distance is greater than the radius, the point lies outside. If it's equal to the radius, the point lies on the circle. And if it's less than the radius, you guessed it right, the point will lie inside the circle.

hope it's help you

7 0
3 years ago
Are the expressions below equivalent 3(4x+8) 12x+24
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Yes they are equivalent
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4 years ago
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Free_Kalibri [48]
What you do first is add the books 42 + 85 + 69 which equals 196. Then divide 196 by 7 and you get 28 :)
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4 years ago
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Javier's fuel tank holds 12 3/4 gallons of gasoline when completely full. He had some gas in the tank and added 10.3 gallons of
GenaCL600 [577]

Answer:

2.45 gallons of gasoline were in the tank before.

Step-by-step explanation:

Consider the provided information.

The tank can hold 12\frac{3}{4} gallons of gasoline when completely full. He had some gas in the tank and added 10.3 gallons of gasoline to fill it completely.

We need to find: How many gallons of gasoline were in the tank before Javier added some?

For this, we need to subtract added gallons of gasoline from the capacity of the tank.

12\frac{3}{4}-10.3=\frac{51}{4}-10.3

=12.75-10.3

=2.45

Hence, 2.45 gallons of gasoline were in the tank before.

6 0
3 years ago
The length of a rectangle is 5959 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
lorasvet [3.4K]

Length: 2w + 59

width: w

diagonal: (2w + 59) + 2  = 2w + 61

Length² + width² = diagonal²

(2w + 59)² + (w)² = (2w + 61)²

(4w² + 118w + 3481) + w²  = 4w² + 122w + 3721

5w² + 118w + 3481 = 4w² + 122w + 3721

w² + 118w + 3481 = 122w + 3721

w² - 4w + 3481 = 3721

w² - 4w - 240 = 0

a = 1, b = -4, c = -240

w = [-(b) +/- \sqrt{(b)^{2}  - 4(a)(c) }]/2(a)

 = [-(-4) +/- \sqrt{(-4)^{2}  - 4(1)(-240) }]/2(1)

   =  [4 +/- \sqrt{(16  + 960) }]/2        

  = [4 +/- \sqrt{(976) }]/2  

  = [2 +/- 4\sqrt{(61) }]/2  

  = 1 +/- 2\sqrt{(61) }

since width cannot be negative, disregard  1 - 2√61

w = 1 + 2√61  ≈ 16.62

Length: 2w + 59  =  2(1 + 2√61) + 59  = 2 + 4√61 + 59  =  61 + 4√61  ≈ 92.24

Answer: width = 16.62 in, length = 92.24 in

7 0
3 years ago
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