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3 years ago

Multiply(2.3 x 10 -5) (3.1 x 10 12)

Mathematics

1 answer:

pychu [463]3 years ago

5 0

2.3*10-5=18

3.1*10 (dunno what to do with 12, there's no sign) but = 31 (that's w/o the 12)

Now multiply which = 558 (do whatever with the 12 to the equation.

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Tell whether the sequence is arithmetic. If it is, identify the common difference.

Rudik [331]

Answer:

Yes, it is arithmetic with the common difference 2.

Step-by-step explanation:

10-8=2

8-6=2

6-4=2

etc.

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2 years ago

Please help me again

dangina [55]

Answer:

Step-by-step explanation:

Step 1: Solve for x

x + 3x + 2x = 180

6x / 6 = 180 / 6

x = 30

Step 2: Find the measure of angle C

Angle C = 2x

Angle C = 2(30)

Angle C = 60 degrees

Answer: 60

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3 years ago

Alan will spend at most $30 on gifts. So far, he has spent $19. What are the possible additional amounts he will spend?

Ede4ka [16]

Answer:

$11

Step-by-step explanation:

This is because If you subtract 19 from 30 your answer will be 19.

6 0

2 years ago

2.) If ZA = (20 – 2m)º and ZD = (m – 130°, what is the value of m?

vivado [14]

Answer:

m = 50

Step-by-step explanation:

∠ D and ∠ A are vertically opposite angles and are congruent , then

m - 130 = 20 - 2m ( add 2m to both sides )

3m - 130 = 20 ( add 130 to both sides )

3m = 150 ( divide both sides by 3 )

m = 50

3 0

2 years ago

Read 2 more answers

Sec squared 55 - tan squared 55

sergejj [24]

Answer:

sec squared 55 – tan squared 55 = 1

Explanation:

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

6 0

3 years ago