Modular arithmetic is all about finding the remainder from long division (MOD), and the total number of times that a number goes into a division (DIV<span>).</span>
Okay, so -
We have one very important thing here. This little part <em>6 - (-3). </em>
Now, it's essential to remember that when we have two negatives like this, we simply draw a line straight down. It becomes a positive!
So, our question is essentially <em>5 + 6 + 3 - 8 + 4 - 3 = ?</em> instead of <em>5 + 6 - (-3) - 8 + 4 - 3!</em> =)
With that in mind, we simply solve left to right.
<em>11 + 3 - 8 + 4 - 3 = ?</em>
<em>14 - 8 + 4 - 3 = ?</em>
<em>6 + 4 - 3 = ?</em>
<em>10 - 3 = ?</em>
<em>7</em> is our final answer! =)
Answer:
10% of 500, 000 = 50, 000
We are given the following information concerning the three production machines;

Also, we are given the percentage of defective output as follows;

Therefore, if an item is selected randomly, the probability that the item is defective would be;

ANSWER:
The probability that the item is defective would be 0.0415