5.924 g
Step-by-step explanation:
The average weight of a boron atom is 10.811 atomic mass units (AMU). Therefore 3.3 x 10^23 atoms of boron will weight;
3.3 x 10^23 * 10.811 = 3.56763 x 10 ^ 24
One (1) gram = 6.022 x 1023 AMU. Therefore to convert AMU to grams;
3.56763 x 10 ^ 24 / 6.022 x 10^23
= 5.924 g
Learn More:
For more on atomic mass check out;
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Sin D= opp./hyp. = 35/37
cos D= adj./hyp. = 12/37
tan D= opp./ adj. = 35/12
Do length x Width x height to find the volume of something