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postnew [5]
3 years ago
10

Which equation is not equivalent to the other two

Mathematics
1 answer:
Liula [17]3 years ago
7 0

Answer:

y=-4-3x

Step-by-step explanation:

y = -3x - 4

y = -3x + (-4)

y = -4 + 3x

y = -4 - 3x

You might be interested in
A steel pipe which was 16.84 feet long, weighed 20.88 pounds what is the weight of one foot of the steel pipe?
vfiekz [6]
The weight of one foot of the steel pipe is 1.24 pounds or more accurately, 1.239905.... pounds.

This type of problem is solved using cross multiplication. You know the length (16.84 feet), and the weight (20.88 pounds), of the steel pipe. But what you do not know is the weight of one foot of the steel pipe. Since that is what we are solving for, the weight of one foot of the steel pipe will be our x variable.

This is how I set it up...

16.84 1
——— * ———
20.88 x

I came up with this equation. The length of the pipes I put in the numerator (top), and the weight I put in the denominator (bottom). Since 16.84 feet of a steel pipe weighs 20.88 pounds, 1 foot of a steel pipe weighs x pounds. After you have the equation set up you then move on to cross multiplication.

Step 1: Multiply the top number of the first fraction by the bottom number of the second fraction.
16.84*x= 16.84x

Step 2: Multiply the bottom number of the first fraction by the top number of the second fraction.
20.88*1=20.88

Step 3: Set the answers from step 1 and step 2 equal to each other.
16.84x=20.88

Step 4: Divide 16.88 on both sides so x is by itself.
16.84x 20.88
——— = ———
16.84 16.84

And after you divide on each side you have your answer which should be x=1.24
4 0
3 years ago
If the length of a rectangle is 3 feet less then twice its width and the area is 54square feet what are its dimensions
erma4kov [3.2K]
The length (L) of the rectangle can be written as a function of the width (W)L = 2W - 3:
Now since we know Area = Width*Length, we can write the area as a function of the width:
A = L*W = (2W-3)*W
Distributing the W inside the parentheses we have:
A = 2W^2 - 3W
We know the area is 54 ft^2, so we can rewrite it as:
2W^2 - 3W - 54 = 0
Now solve for W by factoring (or by applying the quadratic formula):
2W^2 - 12W + 9W - 54 = 0
Factor out a common 2W from the first two terms and a 9 from the last two terms:
2W(W-6) + 9(W-6) = 0
Regroup the terms to get our fully factored equation:
(2W + 9)(W-6) = 0
This gives us the roots W = 6 and W = -9/2, but width can't be negative so we have width = 6 ft. Then remember that the length L = 2W - 3, so our length is:
L = 2W - 3 = 2(6) - 3 = 12 - 3 = 9
So now we know that our rectangle is 9 feet long and 6 feet wide.
5 0
4 years ago
How do you evaluate 4x+2 when the x=6
Oduvanchick [21]

Answer:

4x1+2=6

Step-by-step explanation:

4x+2=6

4 times 1 equals 4 (4x1=4)

4 + 2 = 6


4 0
3 years ago
Find the GCF of 40 and 60 listing factors for each number in order from least to greatest.
Cloud [144]
40:1,2,4,5,8,10,20,40
60:1,2,3,4,5,6,10,12,15,20,30,60
 The GCF between 40 and 60 is 20
4 0
4 years ago
A rectangular lot is 65 meters wide and 110 meters long.Give the length and width of another rectangular lot that has the same p
xxTIMURxx [149]

Answer:

maybe you have to add

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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