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NISA [10]
3 years ago
12

Ricardo spends 8/9 hour reading the newspaper.he spends 1/4 of the time reading the world news and splits the remaining time equ

ally between the sports news and the comics.how much time does he spend reading the comics?
Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0
If he spends 1/4 reading the news, then he spends 3/4 reading the other stuff

3/4 * 8/9 = 24/36 = 2/3 of an hr ...time spent reading sports and comics

(2/3) / 2 =
2/3 * 1/2 = 2/6 reduces to 1/3....so he spends 1/3 of an hour (or 20 minutes) reading the comics



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Licemer1 [7]

Answer:

- 5.2.1.n is answee

Step-by-step explanation:

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3 years ago
Triangle A B C. Angle C is 90 degrees. Hypotenuse A B is 13, adjacent B C is 5, opposite A C is 12.
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Answer:

sin = opp/hyp

sin B = 12/13

sin B = 0.923

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3 years ago
Find the area. The figure is not drawn to scale. Hint: Find the sum of the areas of 2 triangles and 2 parallelograms.
shepuryov [24]

Answer:

d. None of the above

Step-by-step explanation:

✔️Area of triangle 1 = ½*b*h

b = 11 in.

h = 3 in.

Area of triangle 1 = ½*11*3 = 16.5 in.²

✔️Area of triangle 2 = ½*b*h

b = 8

h = 9

Area of triangle 2 = ½*8*9 = 36 in²

✔️Area of parallelogram 1 = b*h

b = 11 in.

h = 9 in.

Area of parallelogram 1 = 11*9 = 99 in.²

✔️Area of parallelogram 1 = b*h

b = 9 in.

h = 11 in.

Area of parallelogram 2 = 9*11 = 99 in.²

✅Total area = 16.5 + 36 + 99 + 99 = 250.5 in.²

7 0
3 years ago
The shear strength of each of ten test spot welds is determined, yielding the following data (psi). 409 378 358 362 389 404 415
dybincka [34]

Answer:

a. Average shear strength = 385.3 ; standard deviation of shear strength is ±19.25

b. At 95%, X = 1.645σ + μ

c. P(X ≤ 400) = 27.77% = 0.2777

Step-by-step explanation:

Mean = (409 + 378 + 358 + 362 + 389 + 404 + 415 + 375 + 367 + 396)/10

Mean = 3853/10

Mean = 385.3

Therefore, Average shear strength = 385.3

Variance = (409 - 385.3)² + (378  - 385.3)²+ (358  - 385.3)² + (362  - 385.3)²+ (389  - 385.3)²+ (404  - 385.3)²+ (415  - 385.3)²+ (375  - 385.3)²+ (367  - 385.3)²+ (396 - 385.3)²/10

Variance = 3704.1/10 = 370.41

Standard deviation = √370.41 = 19.25

Therefore, standard deviation of shear strength is ±19.25

b. Using normal distribution table at 95%, z = 1.645

z= (X - μ)/σ  

Therefore X = 1.645σ + μ

c. X = 400; μ= 385.3 ; σ = 19.25

z= (X - μ)/σ

z= (400 - 385.3)/19.25

z = 0.764

Using the normal distribution table, P = 0.2777

P(X ≤ 400) = 27.77%

8 0
3 years ago
Esperanza decided to purchase a vehicle with a 15999 MSRP at a 4% interest rate for 6 years the dealership offered her a 1700 ca
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Answer:

$223.71

Step-by-step explanation:

We are given the following information

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  • Cash-back incentive=$1700
  • Annual Interest Rate=4%=0.04
  • Loan Duration=6 years

We use the loan repayment formula

Monthly Payment, A=\dfrac{P*r(1+r)^n}{(1+r)^n-1}

Where:

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  • Monthly Interest Rate, r=0.04/12
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A=\dfrac{14299*\frac{0.04}{12}(1+\frac{0.04}{12})^{72}}{(1+\frac{0.04}{12})^{72}-1}\\=\$223.71

Esperanza can expect to pay $223.71 monthly.

4 0
3 years ago
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