Question

A rectangle has a length of 38 meters less than 8 times its width. If the area of the rectangle is 4050 square meters, find the length of the rectangle.

Answer 1

Let

• width be x
• Length=8x-38
• Area=4050m^2

We know

$\boxed{\sf Area =Length\times Width}$

$\\ \sf\longmapsto x(8x-38)=4050$

$\\ \sf\longmapsto 8x^2-38x=4050$

$\\ \sf\longmapsto 8x^2-38x-4050=0$

• By solving

$\\ \sf\longmapsto x=\dfrac{81}{4}\:or\:x=25$

• Take x as 25

$\\ \sf\longmapsto Length=8x-38=8(25)-38=200-38=162m$