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2 years ago

Graphing Absolute Value Equations

Mathematics

2 answers:

mr_godi [17]2 years ago

7 0

Answer:

The way I would like to solve this would be by using transformations. The standard form for transformation is a|b(x-h)|+k. Here, " - " is the a. Whenever a is < 0, it reflects across x-axis. The opposite sign of C is the value of vertical symmetry. So, vertical symmetry is, -(-4), which is, 4. (-(c), d ) is how you find the vertex. Here, opposite of c is 4. There is no d so it will be 0. So, the vertex is (4,0)

Step-by-step explanation:

Tip : Hey dudes and dudedas, use the following link to graph the any equations using online calculator. It will make your life, much more easier.

w-w-w desmos cam / practice

Thank me later.

Note : I disorted the link but I am sure that you are smart enough to find it out or type desmos in google.

MrMuchimi2 years ago

6 0

One way is to use transformations, so if you did then move the absolute value equation 4 units to the right then reflect it over the x axis

anyway
the vertex is at (4,0)
the line to the left of (4,0) is y=x-4
the line on the right is y=-x+4

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Eloise made a list of some multiples of 8/5 write 5 fractions that can be in Eloise list

alexgriva [62]

This question is asking for a list of fractions, that when you pull out common factors, they will all simplify back to the 8/5 fraction.

So if 2 is the common factor, you multiply the numerator and denominator by 2.

2: (8*2)/(5*2)= 16/10

3: (8*3)/5*3)= 24/15

4: (8*4)/(5*4)= 32/20

5: (8*5)/(5*5)= 40/25

10: (8*10)/5*10)= 80/50

Eloise's Potential List:
16/10, 24/15, 32/20, 40/25, 80/50

If you simplify any of these fractions above, you will get 8/5 again.

To work backwards:
80/50: 10 goes into 80, 10 goes into 50= 8/5

16/10: 2 goes into 16, 2 goes into 10= 8/5

Hope this helps! :)

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Step-by-step explanation:

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Step-by-step explanation:

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Please help me with these two math problems that I do not quite understand. This is urgent!

g100num [7]

Answer:

1) $a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19$

2) $a_{10}=4+8(10-1)\Rightarrow a_{10}=76$

Step-by-step explanation:

1) To write an Arithmetic Sequence, as an Explicit Term, is to write a general formula to find any term for this sequence following this pattern:

$a_{n}=a_{1}+d(n-1)\Rightarrow \left\{\begin{matrix}a_{n}=n^{th}\: term\\a_1=1st \: term \\d=\: difference\\n=n^{th}\, term\end{matrix}\right.$

<em>"Write an explicit formula for each explicit formula A(n)=-1+(n-1)(-2)"</em>

This isn't quite clear. So, assuming you meant

Write an explicit formula for each term of this sequence A(n)=-1+(n-1)(-2)

As this A(n)=-1+(n-1)(-2) is already an Explicit Formula, since it is given the first term $a_{1}=-1$ the common difference $d=-2$ let's find some terms of this Sequence through this Explicit Formula:

$a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19$

2) $(4,12,20,28, ..)$ In this Arithmetic Sequence the common difference is 8, the first term value is 4.

Then, just plug in the first term and the common difference into the explicit formula:

$a_{10}=4+8(10-1)\Rightarrow a_{10}=76$

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