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avanturin [10]
3 years ago
10

A college entrance exam company determined that a score of 2222 on the mathematics portion of the exam suggests that a student i

s ready for​ college-level mathematics. To achieve this​ goal, the company recommends that students take a core curriculum of math courses in high school. Suppose a random sample of 150150 students who completed this core set of courses results in a mean math score of 22.722.7 on the college entrance exam with a standard deviation of 3.93.9. Do these results suggest that students who complete the core curriculum are ready for​ college-level mathematics? That​ is, are they scoring above 2222 on the math portion of the​ exam? Complete parts​ a) through​ d) below.
Mathematics
1 answer:
kolbaska11 [484]3 years ago
7 0

Answer:

Yes, Students are scoring above 2222 on the math portion of the​ exam.

Step-by-step explanation:

We are given that a college entrance exam company determined that a score of 2222 on the mathematics portion of the exam suggests that a student is ready for​ college-level mathematics i.e., population mean is 22.

Null Hypothesis, H_0 : \mu = 22 {Students are scoring equal to 2222 on the math portion of the​ exam}

Alternate Hypothesis, H_0 : \mu > 22 {Students are scoring above 2222 on the math portion of the​ exam}

Also, a random sample of 150 students who completed this core set of courses results in a mean math score of 22.7 on the college entrance exam with a standard deviation of 3.93 i.e.;

Sample mean, Xbar = 22.7    and Sample standard deviation, s = 3.93

The Test statistics is given by;

                            Z = \frac{Xbar -\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

Test Statistics = \frac{22.7 -22}{\frac{3.93}{\sqrt{150} } } ~ t_1_4_9

                        = 2.1815

Since, we are not given with the significance level, so we assume it to be 5%. At 5% significance level t table gives critical value of 1.6578 at 149 degree of freedom. Since our test statistics is more than the critical value so we reject null hypothesis as our test statistics fall in the rejection region.

Therefore, we conclude that Students are scoring above 2222 on the math portion of the​ exam.

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1.D) Procedure results in a binomial distribution.

2. B) Procedure results in a binomial distribution.

Step-by-step explanation:

The binomial distributions has following properties.

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The answer is :

sal must repair 320 computers in a year to break even.

Step-by-step explanation:

The break even point in a business is the point at which the total costs and the total revenue in a business are equal.

In order to calculate sal's break even point, we will first of all calculate the total costs incurred during the business year, then using the selling price (repairing price), we will calculate how many computers will be repaired to reach the incurred cost. This is done as follows:

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Next, since we know that sal requires $75 in parts and labor to fix a computer, we will calculate the net price charged for each computer fixed as follows:

Net price charged = Priced charged for fixing each computer - Cost incurred in fixing each computer

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break even point = cost of rent for one year ÷ net price charged

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Therefore, by the time sal repairs 320 computers during the year, he must have covered the costs incurred in operations, every additional repair, becomes a profit.

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