Answer: 125
Step-by-step explanation:
First, solve for x in the first equation.
1) Subtract 1 from both sides.
2x = 4
2) Divide by 2 on both sides.
x = 2
Next, substitute the value of x into the second expression.
(2 + 3)^3
= 5^3
= 125
That'd be true only if the value of "s" is the exact same one for both
namely if sec(s) = cos(s)
then solving for "s"
thus
![\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)} \\\\\\ thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s) \\\\\\ \pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides} \\\\\\ cos^{-1}(\pm 1)=cos^{-1}[cos(s)]\implies cos^{-1}(\pm 1)=\measuredangle s](https://tex.z-dn.net/?f=%5Cbf%20sec%28s%29%3Dcos%28s%29%5Cqquad%20but%5Cimplies%20sec%28%5Ctheta%29%3D%5Ccfrac%7B1%7D%7Bcos%28%5Ctheta%29%7D%0A%5C%5C%5C%5C%5C%5C%0Athus%5Ccfrac%7B1%7D%7Bcos%28s%29%7D%3Dcos%28s%29%5Cimplies%201%3Dcos%5E2%28s%29%5Cimplies%20%5Cpm%20%5Csqrt%7B1%7D%3Dcos%28s%29%0A%5C%5C%5C%5C%5C%5C%0A%5Cpm%201%3Dcos%28s%29%5Cimpliedby%20%5Ctextit%7Bnow%20taking%20%7Dcos%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Acos%5E%7B-1%7D%28%5Cpm%201%29%3Dcos%5E%7B-1%7D%5Bcos%28s%29%5D%5Cimplies%20cos%5E%7B-1%7D%28%5Cpm%201%29%3D%5Cmeasuredangle%20s)
The answer should be 3 hours and 45 minutes if i did the math in my head correctly
Answer:
The expressions here are;
6 + 5w
3-16v
4v+ 1
7-v
Step-by-step explanation:
Here, out of the given set, we want to choose all options that are expression.
To do this, we should understand that expressions do not have the equality sign like equations
So expressions are those in the set in which we do not have an equality sign
The right answer is thus;
6 + 5w
3-16v
4v + 1
7-v
Answer:
as x tends to infinity y=infinity
as x tends to 1 y=infinity
x=1 vertical asymptote
