Answer:
The correct answer would be 2 in 4.
According to the question Xo and XO show codominance and express themselves completely when present in heterozygous condition. Cats bearing XoXO show patchwork of black and orange fur and are called tortoiseshell cats.
Xo codes for orange color fur and XO codes for black color fur. In addition, Y chromosome does not contain any gene associated with fur color.
Now, genotype of mother cat is XOXO (orange fur). So, the gametes formed would be XO only.
The genotype of father cat is XoY(black fur). So, the gametes would be Xo and Y.
The cross would lead to the formation of two male cats each having XOY as their genotype and two female cats each with XOXo as their genotype.
Hence, both the male cats would show orange fur and both the female cats would show patchwork of orange and black fur.
Therefore, we can conclude that 2 out of 4 would exhibit tortoiseshell coloring.
Answer:
The effect would be that the green leaves, which contain chloroplasts, containing a chemical called chlorophyll would enable the plants to take in more energy in the form of sunlight, enabling the plants to photosynthesise and grow.
Answer - A
The ratio of a child with clear skin with that of freckled skin is 1:2.
When genotype rr mates with genotype Rr, the following genotypes are expected:
Rr = clear skin dominant
rr= freckled skin