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4vir4ik [10]
4 years ago
13

Help ASAP!! 10 points! will give brainliest to correct answer!!

Mathematics
1 answer:
Vitek1552 [10]4 years ago
6 0

Answer:

The answer to your question is ∠3 = 63°

Step-by-step explanation:

Data

∠2 = 117°

∠3 = x

Process

1.- Angles 2 and 3 are supplementary which means that their addition gives 180°.

So,

                ∠2 + ∠3 = 180

Substitution

                 117° + ∠3 = 180°

Solve for ∠3

                           ∠3 = 180° - 117°

Simplification and result

                            ∠3 = 63°

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Please help<br><br> Select the expressions equivalent to 18 + 3r.
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In a local ice sculpture contest, one group sculpted a block into a rectangular based pyramid. The dimensions of the base were 3
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Answer:

1. The amount of ice needed for the sculpture is 18 m³

2. The amount of fabric needed to manufacture the umbrella is 0.757 m²

3. The height of the cone is 37.5 cm

4. The largest possible storage area which is obtained by attaching the storage area to the back of the building is 87.11 m²

Step-by-step explanation:

1. The volume, V, of a rectangular pyramid = \dfrac{1}{3} \cdot B \cdot h

Where:

B = Base area = Length, L  × Width, W

h = Height of the pyramid = 3.6 m

L = 5 m

W = 3 m

The volume = 1/3 × 5 × 3 × 3.6 = 18 m³

The amount of ice needed for the sculpture is 18 m³

2) The surface area of a cone = π·r·s

s = Slant height

r = Radius of the cone's base = 0.4 m

h = The height of the cone = 0.45m

s = √(0.4² + 0.45²) = (√145)/20

The surface area of the cone = π × 0.4 × (√145)/20 = 0.757 m²

The amount of fabric needed to manufacture the umbrella is 0.757 m²

3) The volume, V of the cone = 150 cm³

The base area, A_b, of the cone = 12 cm²

The height of the cone = h

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Therefore;

\dfrac{1}{3} \times 12 \times  h = 150

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The storage area at the back of the building with three sides = 98 m²

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For maximum area the four sides should be equal, hence dimension of each side = 28/4 = 7

The area of storage space that can be fenced on four sides at the back corner = 7 × 7 = 49 m²

At the back of the building only three sides need fencing, we therefore have;

The side length = 28/3 = 9\frac{1}{3}

The area fenced = \left 9\frac{1}{3} \right  \times 9\frac{1}{3}  = 87\frac{1}{9} \ m^2 = 87.11 m²

Therefore, the largest possible storage area, 87.11 m², is obtained by attaching the storage area to the back of the building.

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4 years ago
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