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3 years ago

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Please help Select the expressions equivalent to 18 + 3r.

1 answer:

andreyandreev [35.5K]3 years ago

3 0

What are the options ???

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Solve 10/12 - 3/8 show your solution as an equation

elena55 [62]

Answer:

11/24

Step-by-step explanation:

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator. Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1. The two fractions now have like denominators so you can subtract the numerators.

This fraction cannot be reduced.

Therefore the answer is 11/24

7 0

3 years ago

Read 2 more answers

Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha

const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

$f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}$

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

$P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35$

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

$P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17$

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95$

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63$

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

$P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06$

Thus, the value of <em>a</em> is 12.06.

7 0

3 years ago

Jacob received a deck of cards for his birthday. The length, width, and height of the card box are shown below. What is the volu

ollegr [7]

The question is incomplete :

The height, width and Lenght isn't Given. However, we can create an hypothetical scenario, with a height 6, length 8 and width 4

Answer:

192 unit³

Step-by-step explanation:

The volume of the card box :

Recall the volume of box formula :

V = length * width * height

Volume = 8 * 6 * 4

Volume = 192 unit³

This is the procedure for any given dimension of the card deck.

6 0

2 years ago

B^-3 = 1/64 what equals b

s2008m [1.1K]

64=2*2*2*2*2*2=2⁶

B⁻³=1/64
1/B³=1/2⁶
B³=2⁶
B=∛2⁶=2⁶/³=2²=4

Answer: B=4

5 0

3 years ago

Is the sum of two rational numbers rational

Advocard [28]

Answer:

no they are irrational

6 0

2 years ago