Question

Can someone help me with the question in the image

Answer 1

Answer:

$m\angle 1=22^o$

Step-by-step explanation:

we know that

In a rhombus, opposite angles are congruent, and consecutive angles are supplementary. The diagonals of a rhombus bisect each other.

so

In this problem

$m\angle 1=m\angle 2=m\angle 3=m\angle 4$

so

$136^o+2m\angle 1=180^o$ ---> by consecutive interior angles

$2m\angle 1=180^o-136^o$

$m\angle 1=22^o$