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Darina [25.2K]
3 years ago
10

If you want to place 9 3/4 inch towel bar in the center of a door that is 27 1/2 wide, how much space will be on each side of th

e towel bar?
Mathematics
2 answers:
marysya [2.9K]3 years ago
3 0
The answer is 11 \frac{5}{6} inches

Step 1. Subtract length of the door from the width of the door:
27 \frac{1}{2} - 9 \frac{3}{4} =  \frac{55}{2} - \frac{39}{4} =\frac{110}{4} - \frac{39}{4}= \frac{71}{4}

Step 2. You want the same space to be on each side of the bar. So, divide the difference from step 1 by 2:
\frac{71}{4} : 2 = \frac{71}{4} :  \frac{2}{1} =\frac{71}{4} * \frac{1}{2}= \frac{71}{6} =  \frac{66+5}{6}= \frac{66}{6}+ \frac{5}{6}=11 \frac{5}{6}
DerKrebs [107]3 years ago
3 0

Answer:

8\frac{7}{8}    

Step-by-step explanation:

It has been given that you want to place 9\frac{3}{4} inch towel bar in the center of a door that is 27\frac{1}{2} wide.

First of all, we will find the total space left on both sides of towel bar by subtracting 9\frac{3}{4} from 27\frac{1}{2}.    

27\frac{1}{2}-9\frac{3}{4}  

\frac{27*2+1}{2}-\frac{9*4+3}{4}    

\frac{54+1}{2}-\frac{36+3}{4}

\frac{55}{2}-\frac{39}{4}

Let us have a common denominator.

\frac{55*2}{2*2}-\frac{39}{4}

\frac{110}{4}-\frac{39}{4}

\frac{110-39}{4}

\frac{71}{4}

Now, we will divide \frac{71}{4} by 2 to find the space left on each side of the towel bar.

\frac{71}{4}\div 2

\frac{71}{4}\div \frac{2}{1}

By flipping the second fraction and multiplying by 1st fraction we will get,

\frac{71}{4}\times \frac{1}{2}

\frac{71}{8}

8\frac{7}{8}

Therefore, 8\frac{7}{8} inch of space will be on each side of the towel bar.

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