Question

If you want to place 9 3/4 inch towel bar in the center of a door that is 27 1/2 wide, how much space will be on each side of the towel bar?

Answer 1

The answer is $11 \frac{5}{6}$ inches

Step 1. Subtract length of the door from the width of the door:
$27 \frac{1}{2} - 9 \frac{3}{4} = \frac{55}{2} - \frac{39}{4} =\frac{110}{4} - \frac{39}{4}= \frac{71}{4}$

Step 2. You want the same space to be on each side of the bar. So, divide the difference from step 1 by 2:
$\frac{71}{4} : 2 = \frac{71}{4} : \frac{2}{1} =\frac{71}{4} * \frac{1}{2}= \frac{71}{6} = \frac{66+5}{6}= \frac{66}{6}+ \frac{5}{6}=11 \frac{5}{6}$

Answer 2

Answer:

$8\frac{7}{8}$    

Step-by-step explanation:

It has been given that you want to place $9\frac{3}{4}$ inch towel bar in the center of a door that is $27\frac{1}{2}$ wide.

First of all, we will find the total space left on both sides of towel bar by subtracting $9\frac{3}{4}$ from $27\frac{1}{2}$.    

$27\frac{1}{2}-9\frac{3}{4}$  

$\frac{27*2+1}{2}-\frac{9*4+3}{4}$    

$\frac{54+1}{2}-\frac{36+3}{4}$

$\frac{55}{2}-\frac{39}{4}$

Let us have a common denominator.

$\frac{55*2}{2*2}-\frac{39}{4}$

$\frac{110}{4}-\frac{39}{4}$

$\frac{110-39}{4}$

$\frac{71}{4}$

Now, we will divide $\frac{71}{4}$ by 2 to find the space left on each side of the towel bar.

$\frac{71}{4}\div 2$

$\frac{71}{4}\div \frac{2}{1}$

By flipping the second fraction and multiplying by 1st fraction we will get,

$\frac{71}{4}\times \frac{1}{2}$

$\frac{71}{8}$

$8\frac{7}{8}$

Therefore, $8\frac{7}{8}$ inch of space will be on each side of the towel bar.