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3 years ago

Can someone help me? Thanks! ;D

Mathematics

2 answers:

Alexandra [31]3 years ago

7 0

Answer:

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² = 5² + 12² = 25 + 144 = 169 ( take the square root of both sides )

x = $\sqrt{169}$ = 13

Agata [3.3K]3 years ago

4 0

Answer:

B - 13

Step-by-step explanation:

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Answer:

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A bucket holds b liters of water. But a jar holds 8 fewer liters than the bucket. How many times can the bucket hold than the ja

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Answer:

b / (b - 8)

Step-by-step explanation:

Given that :

Litres of water held by bucket = b

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The number of times bucket can hold than jar is :

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2 years ago

What is the simplified form of the following expression?

USPshnik [31]

Option C:

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

Solution:

Given expression is

$$\sqrt[3]{\frac{4 x}{5}}$

Note: $\sqrt[3]{125}=\sqrt[3]{{5^3}} = 5$

To find the correct expression for the above simplified expression.

Option A: $\frac{\sqrt[3]{4 x}}{5}$

5 can be written as $\sqrt[3]{125}$ .

$$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{4x}{125} }$

It is not the given simplified expression.

Option B: $\frac{\sqrt[3]{20 x}}{5}$

$$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{20x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4x}{25} }$

It is not the given simplified expression.

Option C: $\frac{\sqrt[3]{100 x}}{5}$

$$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{100x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4 x}{5}}$

It is the given simplified expression.

Option D: $\frac{\sqrt[3]{100 x}}{125}$

$$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}$

It is not the given simplified expression.

Hence Option C is the correct answer.

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

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2 years ago

For which value of a are the graphs of –4 = 3x + 6y and ax – 8y = 12 parallel?

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Answer:

The answer is A) a=-4

Step-by-step explanation:

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2 years ago

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william is thinking of two numbers both numbers are square numbers greater than 1 the sum of numbers is 100 write down two numbe

zheka24 [161]

Answer:

Step-by-step explanation:

At first,

Let start writing the squares of number 0 to 10,

0²=0

1²=1

2²=4

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5²=25

6²=36

7²=49

8²=64

9²=81

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Now,

According to your question,

The two numbers should be square numbers
They should be greater than 1.
Their sum should be 100.

Hence, your given conditions matches with the numbers 64 and 36.

Therefore, the numbers are 64 and 36.

64 and 36 are greater than 1.
64 is a square of 8 and 36 is the square of 6.
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