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lisov135 [29]
4 years ago
10

What is 6/7 to the 90 power

Mathematics
1 answer:
exis [7]4 years ago
7 0
I think its 5.2399561e-76
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How are you in the bet nobody’s not going to help me on this question
Nataliya [291]

Answer:

See below.

Step-by-step explanation:

Party A

y = x^2 + 1

For each value of x in the table, substitute x in the equation with that value and evaluate y.

x = -2: y = (-2)^2 + 1 = 4 + 1 = 5

x = -1: y = (-1)^2 + 1 = 1 + 1 = 2

Do the same for x = 0, x = 1, x = 2

x     y

-2   5

-1    2

0    1

1     2

2    5

Part B

Look at points (-2, 5) and (-1, 2). The change in x from (-2, 5) to (-1, 2) is 1. The change in y is -3.

Now let's look at two other points which have a change in x of 1. Look at points (0, 1) and (1, 2). The change in x from (0, 1) to (1, 2) is 1. The change in y is 1.

You can see that for the first two points, a change of 1 in x produces a change of -3 in y, but for the second two points, the same change of 1 in x produce a change of 1 in y. Since the same change of x does not always produce the same change in y, the function is nonlinear.

Answer: A

4 0
3 years ago
What is 90-45-12. Plzzz
worty [1.4K]

Answer:

33

Step-by-step explanation:

45 is half of 90

So straight away go to 45-12

33

Hope this helps

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6 0
4 years ago
Read 2 more answers
How much time will it take for a bug to travel 5m across the floor if it is traveling at 0.5m/s?
goldenfox [79]

Answer:

10 seconds

Step-by-step explanation:

Every second the bug travels 0.5m/s or 0.5 meters per second.

Given that, every 2 seconds the bug will travel a full 1 meter.

To solve this one can simply divide 5m by 0.5 and get 10 seconds.

5 0
3 years ago
PLEASE HELP!!! WILL GIVE BRAINLEST AWARD FOR MOST DESCRIPTIVE
Rashid [163]
The law of cosines states that:

c^2=a^2+b^2-2abcosC

You already have all the values for the variables with the exception of x so:

x^2=25+100-100cos60

x=√(125-100cos60)

x=√75

x≈8.66 to nearest one-hundredth...
3 0
3 years ago
Question 2
prisoha [69]

Answer:

Please check the explanation.

Step-by-step explanation:

<u>Calculating the area of the outer rectangle:</u>

Given

  • The length outer rectangle = l = 3x - 1
  • The width of outer rectangle = w = 5x + 2

Thus,

The area of the outer rectangle:

A = wl

    = (5x + 2) (3x - 1)

    =5x\cdot \:3x+5x\left(-1\right)+2\cdot \:3x+2\left(-1\right)

     =5\cdot \:3xx-5\cdot \:1\cdot \:x+2\cdot \:3x-2\cdot \:1

      =15x^2+x-2

<u>Calculating the area of the inner rectangle:</u>

Given

  • The length inner rectangle = l = x + 7
  • The width of inner rectangle = w = x

Thus,

The area of the outer rectangle:

A = wl

   = x(x+7)

   = x² + 7

<u>Calculating the area of the shaded region:</u>

As

The area of the outer rectangle = 15x² + x - 2

The area of the inner rectangle = x² + 7

  • The area of the shaded region can be determined by subtracting the area of the inner rectangle from the area of the outer rectangle.

Thus,

shaded region Area = Outer Rectangle Area - Inner Rectangle Area

                                  = 15x² + x - 2 - (x² + 7)

                                   =  15x² + x - 2 - x² - 7

                                   = 14x² + x - 9

Therefore, the Area of the shaded region is: 14x² + x - 9

4 0
3 years ago
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