Answer:
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Step-by-step explanation:
I would first cut off the ends that make a trapezoid and then find the area of the trapezoids and the area of the rectangles.
A trap = (1/2) * h *(b1 + b2)
A rect = L * W
A trap = (1/2) 4 * (6 + 14)
A = (1/2) * 4 * 20
A = 40 (there are 2 trapezoids) 40 * 2 = 80 yds^2
A rect = L * W
A = 12 * 4
A = 48 (there are 2 rectangles) 48 * 2 = 96 yds^2
80 + 96 = 176 yds^2
The difference between the length of arc BD and CE is 1.57 units
<h3>Length of an arc</h3>
length of arc = ∅ / 360 × 2πr
where
- r = radius
- ∅ = central angle
Therefore,
BD = 45 / 360 × 2 × 3.14 × 6 = 1695.6 / 360 = 4.71 units
CE = 45 / 360 × 2 × 3.14 × 8 = 2260.8 / 360 = 6.28 units
Therefore, the difference between the length of arc BD and CE is as follows:
6.28 - 4.71 = 1.57 units
learn more on length of arc here: brainly.com/question/3984590
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Step-by-step explanation:
Store A:
5 bagels for $2.05, 1 bagel for $2.05/5 = $0.41.
Store B:
3 bagels for $1.35, 1 bagel for $1.35/3 = $0.45.
Hence the bagels at Store B are $0.04 more expansive than the bagels at Store A. (C)
Answer:
width = 5 feet
length = 11 feet
Step-by-step explanation:
Using one variable and setting up two expressions equal to the total area of the rectangle will determine the dimensions of the rectangle.
w = width
l = '4 feet less than three times the width' or 3w - 4
Area = length x width
A = w(3w - 4) = 55
Distribute: 3w² - 4w = 55
Set equation equal to '0': 3w² - 4w - 55 = 0
Multiply 3 x -55 = -165 and find two factors with a product of -165 and sum of -4: -15 and 11.
3w² - 15w + 11w - 55
Group and find the GCF (greatest common factor):
3w(w - 5) + 11(w - 5)
(3w + 11)(w - 5) = 0
3w + 11 = 0 and w - 5 = 0
w = -11/3 not possible to have negative measurement
w = 5 feet
Solve for length: 3(5) - 4 = 11 feet