For lines to be perpendicular their slopes must be negative reciprocals of one another, mathematically:
m1*m2=-1
So we first need to find the slope of the reference line.
m=(y2-y1)/(x2-x1)=(7-2)/(-1--5)=5/4
So the perpendicular line will have a slope of:
5m/4=-1
m=-4/5
So our perpendicular line so far is:
y=-4x/5+b, now we can use point (3,-1) to solve for the y-intercept, "b"
-1=-4(3)/5+b
-1=-12/5+b
-5/5+12/5=b
7/5=b
So the line is:
y=-4x/5+7/5 or more neatly
y=(-4x+7)/5
y=-0.8x+1.4
Answer:
c = 4 A
Step-by-step explanation:
The given function P(c) = - 15 c (c-8) is actually quadratic function:
P(c) = - 15c² + 120c or parabola
The standard form of a quadratic function is:
y = ax² + bx + c
For which x is the maximum of the parabola we can find with this formula
x = - b/2a
in this case a = -15 and b = 120 and input variable is current c
c = - 120/(2 · (-15)) = - 120/ (-30) = 4 A
c = 4 A
God with you!!!
Answer:
substituting & graphing
Step-by-step explanation:
Answer:
10 3/40
Step-by-step explanation: hope i helped
Answer:
(-1,8)
Step-by-step explanation:
Look at the top point of the parabola type thing. I know that it's not a parabola, but IDRK how else to describe it. If you see the top point at one of the answers, it is most likely correct.
