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artcher [175]
3 years ago
9

The perimeter of a rectangular garden is 168 feet. If the length of the garden is 6 feet more than twice the width, what is the

length of the garden? Length = 52.5 feet Length = 54 feet Length = 58 feet Length = 48 feet
Mathematics
1 answer:
worty [1.4K]3 years ago
3 0

Answer:

Length= 58

width= 26

Step-by-step explanation:

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Solve the system of linear equations by substitution.<br> 2x-y=3<br> x+5y=14
Arturiano [62]

Answer:

x= 29/11 or y= 25/11

Step-by-step explanation:

2x - y= 3 ...........equation 1

x + 5y= 14 ............equation 2

Make x the subject of the formula in equation 2

x= 14 - 5y ..............equation 3

Substitute x=14 - 5y in equation 1

2(14- 5y) - y=3

28 - 10y - y=3

Collect like terms

-10y - y=3 - 28

-11y= -25

divide both sides by coefficient of y

-11y/-11 = -25/-11

y= 25/11

Substitute y= 25/11 in equation 3

x=14 - 5(25/11)

x= 14 - 125/11

x= 29/11

6 0
3 years ago
What are the coordinates of the point labeled C in the graph?
kykrilka [37]
The answer is B x axis first
6 0
3 years ago
Read 2 more answers
I wasn’t so sure on how to solve this, anyone mind helping me?
sweet-ann [11.9K]

Answer:

Rays: A, B, C, D - 4 rays for each.

Line segments: AB, BD, DC, CA.

7 0
2 years ago
Please! Solve f(x)-g(x) if f(x)=1/2x^4 - x^2 and g(x)= 3/4x^4 +3x^3 - x^2
igomit [66]

Answer:

f(x)-g(x)=\frac{-1}{4}x^{4}-3x^{3}

Step-by-step explanation:

This is a subtraction between polynomials, since both functions are polynomials, hence, to solve the problem with need to perform the subtraction, by coefficients.

f(x)= \frac{1}{2}x^{4}+0x^{3}-x^{2}\\\\g(x)=\frac{3}{4}x^{4}+3x^{3}-x^{2}

By performing the subtraction, we have:

f(x)-g(x)=\frac{-1}{4}x^{4}-3x^{3}

6 0
3 years ago
Bhairav collected Rs.600 in his piggy bank by putting in Rs.2 and Rs.5 coins. The number of Rs.5 coins are twice as many as Rs.2
Anna [14]

Answer:

100 Rs 5 coins and 50 Rs 2 coins

Step-by-step explanation:

Bhairav collected Rs.600 in his piggy bank by putting in Rs.2 and Rs.5 coins. The number of Rs.5 coins are twice as many as Rs.2 coins

Let x be the number of 5 coins

and y be the number of 2 coins

The number of Rs.5 coins are twice as many as Rs.2 coins

x=2y

5x+2y=600

Replace x with 2y

5x+2y=600\\5(2y)+2y=600\\10y+2y=600\\12y=600\\y=50

x=2y\\x=2(50)\\x=100

So 100 Rs 5 coins and 50 Rs 2 coins

7 0
3 years ago
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