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3 years ago

How do u write 0.125 as a ratio

Mathematics

1 answer:

Nonamiya [84]3 years ago

6 0

0.125 as a ration $= \frac{125}{1000} = \frac{1}{8}$

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The measure of the hypotenuse is? (side c)

Sliva [168]

Answer: 25
explanation:
7² + 24² = c²
49 + 576 = c²
625 = c²
c = √625
c= 25

or just know some pythagorean triples

4 0

3 years ago

Read 2 more answers

19/92 written as a percentage

Solnce55 [7]

Answer:

20.65%

Step-by-step explanation:

$\frac{19}{92} \\ \\ = \frac{19 \times 100}{92} \% \\ \\ = \frac{1900}{92} \% \\ \\ = 20.6521739 \%\\ \\ = 20.65\%$

4 0

3 years ago

A boy flying a kite lets out 300 feet of string. The height of the kite is 185 feet. What is the angle

Nataliya [291]

Answer:

The string, the height and the ground form a right triangle

The hypotenuse = 300

height =185 = opposite side

sine of the angle = 185 / 300 = 0.6166666667

arc sine (.616666666666) =

38.073 degrees

Step-by-step explanation:

4 0

4 years ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.