Answer:
That's a lot of points for a question like this
Find the total ° of the shape.
(5-2) x 180°= 540°
x+21°+x = 540°-105°-154°-88°
2x+21° = 193°
2x = 193°-21°
2x = 172°
x = 172° ÷ 2
x = 86°
Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Answer:
C. -21 is your answer
Step-by-step explanation:
Solve for t. Isolate the variable t in the first equation, then use the number gotten to solve the second equation.
3t - 7 = 5t
First, subtract 3t from both sides
3t (-3t) - 7 = 5t (-3t)
-7 = 5t - 3t
-7 = 2t
Isolate the variable (t). Divide 2 from both sides
(-7)/2 = (2t)/2
t = -7/2
t = -3.5
Plug in -3.5 for t in the second equation
6(t) =
6(-3.5) =
6(-3.5) = -21
C. -21 is your answer
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