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2 years ago

Is it rational or irrational

Mathematics

2 answers:

Nimfa-mama [501]2 years ago

7 0

Math is real hard but I think irrational don’t quote me on that

lys-0071 [83]2 years ago

7 0

I also believe that the answer is irrational

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Please help me so confused Solve. x^2 + 3x − 7 = 0 Enter your answers, as exact values, in the boxes. x = or x =

Rzqust [24]

Answer:

x = -1/2 ( 3±sqrt(37))

Step-by-step explanation:

x^2 + 3x − 7 = 0

Add 7 to each side

x^2 + 3x =7

Using complete the square

Taking the coefficient of x

Divide by 2

3/2

Square it

(3/2)^2 = 9/4

Add this to each side

x^2 + 3x+ 9/4 = 7+9/4

( x+ 3/2) ^2 = 28/4 + 9/4

( x+ 3/2) ^2 = 37/4

Take the square root of each side

x+3/2 = ±sqrt(37/4)

x+3/2 = ±sqrt(37) / sqrt(4)

x+ 3/2 = ±sqrt(37) / 2

Subtract 3/2 from each side

x = -3/2 ±sqrt(37) / 2

x = -1/2 ( 3±sqrt(37))

6 0

3 years ago

Read 2 more answers

You have just used the network planning model and found the critical path length is 30 days and the variance of the critical pat

ollegr [7]

Answer: The probability that the project will be completed in 33 days or less is equal to 0.73 .

Step-by-step explanation:

We assume that this is a normally distribution.

Given : The critical path length is 30 days .

i.e. Population mean = $\mu=30$

Variance : $\sigma^2=25$

Then, standard deviation : $\sigma=\sqrt{25}=5$

Z-score : $z=\dfrac{x-\mu}{\sigma}$

The value of z corresponding to 33 = $z=\dfrac{33-30}{5}=0.6$

Now, the p-value = $P(x\leq33)=P(z\leq0.6)=0.7257469\approx0.73$

Hence, the probability that the project will be completed in 33 days or less is equal to 0.73.

6 0

2 years ago

Read 2 more answers

Quadrilateral ABCD is similar to Quadrilateral EFGH. Diagonal AC has length 7 and diagonal EG has length 13. What is the scale f

olasank [31]

Answer:

$\large \boxed{\text{A. }\dfrac{13}{7}\text{; B. }\dfrac{17}{14} \text{; C. 507 in}^{2}}$

Step-by-step explanation:

A. Scale factor

When you dilate an object by a scale factor, you multiply its line lengths by the same number.

If EF/AB = 13/7, the scale factor is 13/7.

B. Length of EF

$\begin{array}{rcl}\dfrac{EF}{AB} & = & \dfrac{13}{7}\\\\\dfrac{EF}{\frac{17}{26}} & = & \dfrac{13}{7}\\\\EF & = & \dfrac{13}{7}\times\dfrac{17}{26}\\\\ & = &\dfrac{1}{7}\times\dfrac{17}{2}\\\\ & = & \mathbf{\dfrac{17}{14}}\\\end{array}\\\text{The length of EF is $\large \boxed{\mathbf{ \dfrac{17}{14}}}$}$

C. Area of EFGH

If the lengths in a shape are all multiplied by a scale factor, then the areas will be multiplied by the scale factor squared.

ABCD is dilated by a scale factor of 13/7, so its area is dilated by a scale factor of

$\left(\dfrac{13}{7} \right)^{2} = \dfrac{169}{49}$

The area of its dilated image EFGH is

$\text{Area of EFGH} = \text{147 in}^{2} \times \dfrac{\text{169}}{\text{49}} = 3 \times 169\text{ in}^{2} = 507 \text{ in}^{2}\\\\\text{The area of EFGH is $\large \boxed{\textbf{507 in}^{\mathbf{2}}}$}$