Answer:
2222222222
Step-by-step explanation:
I hope this helps you
42/98
2.3.7/2.7.7
3/7
Using the quadratic equation instead of calculus, you can find the x coordinate of the vertex as it will be the midpoint of the two x coordinates of the zeros...
x=(-3±√-27)/2
x=-1.5±√-6.75
That the second term is imaginary does not matter because we will add or subtract this value from -1.5, thus the midpoint of the zeros, the x coordinate of the vertex is -1.5. And to find the value of y for the vertex we just find the value of y when x=-1.5
y(-1.5)=6.75
Since y>0, the vertex is above the x-axis.
Answer:
1) (2x + 2)(x + 2)
2) 2(x + 1)(x - 1)
3) (x^2 + 3)(x^2 - 3)
4) 2x(x + 5)(x - 2)
5) (5x + 2y)(5x - 2y)
Step-by-step explanation:
1)
2x^2 + 6x + 4
= 2x^2 + 4x + 2x + 4
= 2x(x + 2) + 2(x + 2)
= (2x + 2)(x + 2)
2)
2x^2 - 2
= 2(x^ 2 - 1) (The difference of two squares)
= 2(x + 1)(x - 1)
3)
x^4 - 9 (The difference of two squares)
=(x^2 + 3)(x^2 - 3)
4)
2x^3 + 6x^2 - 20x
= 2x(x^2 + 3x - 10)
= 2x(x + 5)(x - 2)
5)
25x^2 - 4y^2 (The difference of two squares)
= (5x + 2y)(5x - 2y)
68x87 i think?
sorry if that isnt right..