If cba represents three numbers multiplied together, what property allows you to rearrange the factors to read abc?

Solve 3x - 5 + x = 31. -12 -9 9 12

steposvetlana [31]

Answer: 9

-12 results in -53

-9 results in -41

9 results in 31

12 results in 43

8 0

3 years ago

4. Dean Pelton wants to perform calculations to impress the accreditation consultants, but upon asking for information about GPA

Leya [2.2K]

Answer:

the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

Step-by-step explanation:

Let assume that n should represent the number of the students

SO, $\bar x$ can now be the sample mean of number of students in GPA's

To obtain n such that $P( \bar x \leq 2.3 ) \leq .04$

⇒ $P( \bar x \geq 2.3 ) \geq .96$

However ;

$E(x) = \int\limits^4_2 Dx (2+e^{-x} ) 4x = D \\ \\ = D(e^{-x} (e^xx^2 - x-1 ) ) ^D_2 = 12.314 D$

$E(x^2) = D\int\limits^4_2 (2+e^{-x})dx \\ \\ = \dfrac{D}{3}[e^{-4} (2e^x x^3 -3x^2 -6x -6)]^4__2}}= 38.21 \ D$

Similarly;

$D\int\limits^4_2(2+ e^{-x}) dx = 1$

⇒ $D*(2x-e^{-x} ) |^4_2 = 1$

⇒ $D*4.117 = 1$

⇒ $D= \dfrac{1}{4.117}$

$\mu = E(x) = 2.991013 ; \\ \\ E(x^2) = 9.28103$

∴ $Var (x) = E(x^2) - E^2(x) \\ \\ = .3348711$

Now; $P(\bar \geq 2.3) = P( \bar x - 2.991013 \geq 2.3 - 2.991013) \\ \\ = P( \omega \geq .691013) \ \ \ \ \ \ \ \ \ \ (x = E(\bar x ) - \mu)$

Using Chebysher one sided inequality ; we have:

$P(\omega \geq -.691013) \geq \dfrac{(.691013)^2}{Var ( \omega) +(.691013)^2}$

So; $(\omega = \bar x - \mu)$

⇒ $E(\omega ) = 0 \\ \\ Var (\omega ) = \dfrac{Var (x_i)}{n}$

∴ $P(\omega \geq .691013) \geq \dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2}$

To determine n; such that ;

$\dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2} \geq 0.96 \\ \\ \\ (.691013)^2(1-.96) \geq \dfrac{-3348711*.96}{n}$

⇒ $n \geq \dfrac{.3348711*.96}{.04*(.691013)^2}$

$n \geq 16.83125$

Thus; we can conclude that; the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

5 0

3 years ago

The sum of two numbers is 10. One number is 4 times the other. Find the number

Lesechka [4]

How easy! Just list all the factors that add up to ten.

10 + 0

9 + 1

8 + 2

7 + 3

6 + 4

5 + 5

Which ones match the requirements?

8 0

3 years ago

Read 2 more answers

Someone help me out please

enot [183]

Hey there!

150 = 8x + 6y

↠ 150 = 8x + 6(9)

↠ 8x + 6(9) = 150

↠ 8x + 54 = 150

SUBTRACT 54 to BOTH SIDES

8x + 54 - 54 = 150 - 54

CANCEL out: 54 - 54 because that gives you 0

KEEP: 150 - 54 because helps solve for x

↣150 - 54 = 96↢

NEW EQUATION: 8x = 96

DIVIDE 8 to BOTH SIDES

8x/8 = 96/8

CANCEL out: 8/8 because that gives you 1

KEEP: 96/8 because that gives the value of x

96/8 = x

x = 12

Answer: x = 12

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

3 0

3 years ago

How are the values of -4^3 and 4^-3 alike and how do they differ?

BartSMP [9]

Answer:

(-4)³ = -64

(4)⁻³ = 1/64

Step-by-step explanation:

$( - 4) {}^{3} = ( - 4) \times ( - 4) \times ( - 4) = - 64 \\$

${4}^{ - 3} = (\frac{1}{4} ) {}^{3} \\$

$({ \frac{1}{4} )}^{3} = \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} = \frac{1}{64} \\$

4 0

2 years ago