What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
42.41 cubic meters
The volume of a cylinder is bh where b is the area of the base and h is the height of the cylinder. And since the area of a circle is pi r^2, we have this equation for the volume of a cylinder
V = pi*r^2*h
Now substitute, the known values for r and h, then calculate the result:
V = pi*r^2*h
V = 3.14159*3^2*1.5
V = 3.14159*9*1.5
V = 42.411465
V = 42.41
So the volume of the coal pile is 42.41 cubic meters.
Answer:
The Point C shows the location of 5-2i in the complex plane: 5 points to the right of the origin and 2 points down from the origin.
Step-by-step explanation:
We have the complex number 5-2i and we have to show the location of the point that represents that number in the complex plane
In the complex plane the real numbers are located in the horizontal axis, increasing to the right. The positives real numbers are at the right of the origin and the negatives to the left.
The complex numbers are located in the vertical axis, with the positives over the origin and the negatives below the origin.
This complex number 5-2i is the sum of a real part (5) and a imaginary part (-2i), so the point will be 5 units rigth on the horizontal axis (for the real part) and 2 units down in the vertical axis (for the imaginary part).
Answer:
The answer to this question can be defined as follows:

Step-by-step explanation:
please find attached file.
Answer:942 is the answer
Step-by-step explanation:
Given : Radius= 5
Height =6
To Find:
Volume = 2
r²h
= 2*3.14*5²*6
= 942