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svp [43]
3 years ago
5

Which point shows the location of 5 – 2i on the complex plane below? On a coordinate plane, points A, B, C, and D are shown. Poi

nt A is 2 units to the left of the origin and 5 points up from the origin. Point B is 2 points to the right of the origin and 5 points down from the origin. Point C is 5 points to the right of the origin and 2 points down from the origin. Point D is 5 points to the left of the origin and 2 points down from the origin. point A point B point C point D

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

The Point C shows the location of 5-2i in the complex plane: 5 points to the right of the origin and 2 points down from the origin.

Step-by-step explanation:

We have the complex number 5-2i and we have to show the location of the point that represents that number in the complex plane

In the complex plane the real numbers are located in the horizontal axis, increasing to the right. The positives real numbers are at the right of the origin and the negatives to the left.

The complex numbers are located in the vertical axis, with the positives over the origin and the negatives below the origin.

This complex number 5-2i is the sum of a real part (5) and a imaginary part (-2i), so the point will be 5 units rigth on the horizontal axis (for the real part) and 2 units down in the vertical axis (for the imaginary part).

user100 [1]3 years ago
7 0

Answer:

c. point c

Step-by-step explanation:

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Find the equation of the line that passes through (1, -1) and is parallel to
daser333 [38]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

2x+y-3=0\implies y=\stackrel{\stackrel{m}{\downarrow }}{-2} x+3 \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line with a slope of -2 and that passes through (1 , -1)

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad \qquad \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{-2}(x-\stackrel{x_1}{1}) \\\\\\ y+1=-2x+2\implies y=-2x+1

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So we want to see which number line shows the sum 1.5 + 2.5. We will see that the correct option is <u>"An arrow goes from 0 to 1. 5 and from 1. 5 to 4"</u>

So the number line usually starts at 0 and goes to the first number, 1.5 in this case.

Then, it moves accordingly to the second number, 2.5 (so it will move 2.5 units to the right)

So the number line should start at 0 and move to the right until it meets 1.5 + 2.5 = 4.

From the options, the only that is correct is:

<u><em>"An arrow goes from 0 to 1. 5 and from 1. 5 to 4"</em></u>

If you want to learn more about number lines, you can read:

brainly.com/question/10851163

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