Answer: The mid-point of AC easy to calculate.
It is at ((5+3)/2,(5−1)/2)=(4,2) .
What you really asked was the coordinates of the point 3/4 of the way from A to C, and the calculation is very similar. I think of it as giving a “weighting” to the nearest point. So in this case we give a weighting of 3 to point C and 1 to point A.
Then =((5+3∗3)/4,(5−1∗3)/4)
So =(3½,½) .
CHECK:
Distance
2=(5−3½)2+(5−½)2
=(3/2)2+(9/2)2=9/4+81/4
=90/4
So the distance =310‾‾‾√/2
And the distance
2=(3½−3)2+(½+1)2
=1/4+9/4=10/4
And so the distance BC is 10‾‾‾√/2 which is indeed one third of the distance AB.
Step-by-step explanation:
Answer:
20km
Step-by-step explanation:
we need to find c, which is the hypotenuse of the right triangle.
we know the lengths of the legs, which are given as 16km and 12km
you might notice that 16km and 12km can both be divided by 4, which will then give is 4 and 3.
3,4,5 is a pythagorean triple-(the sums of the squares of 3 and 4 is equal to the square of 5).
The triple can be proved:
3²+4²=5²
9+16=25
25=25
that means the lengths of the triangle is a multiple of the triple 3, 4, and 5
so that means that c is 5*something
since 12 and 16 are 3*4 and 4*4 respectively, that means that c must be 5*4=20km
Hope this helps!
Given:
Initial population = 100 algae
Growth rate = 30% per day.
Time = 5 days
To find:
The future amount of population.
Solution:
The exponential growth model is
where, a is the initial value, r is the rate of interest in percent and t is time period.
Substituting the given values, we get
Now, solve this.
Therefore, the future value is 371.293 algae.
The first thing you should know in this case is that a circumference has a total measure in 360 degrees.
We have then that the formula to find EG in this case is:
EG + GF + FE = 360
We cleared EG:
EG = 360-GF-FE
We substitute the values:
EG = 360-83-66
EG = 211
Answer
EG = 211 degrees.
B. 5
the minimum is where the end of the left tail is. the first quartile is where the beginning of the box is, the mid is in the middle of the box, the 3rd quartile is at the end of the box and the maximum is the end of the right tail.