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Tamiku [17]
4 years ago
11

When 7 is subtracted from five times a number, the result is greater than twice the sum of the number and 4. Find all the number

s that satisfy the inequality
Mathematics
1 answer:
hichkok12 [17]4 years ago
3 0

Given :

When 7 is subtracted from five times a number, the result is greater than twice the sum of the number and 4.

To Find :

All the numbers that satisfy the inequality.

Solution :

Let , the number is x .

Mathematical expression for first term is :

5x - 7

Mathematical expression for second term is :

2(x + 4)

Now , comparing both the expression by given constrain.

5x - 7 > 2(x + 4)\\\\5x-7>2x+8\\\\3x>15\\\\x>5

So, all the numbers that satisfy the inequality are greater than 5.

Hence , this is the required solution.

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PLEASE I NEED THIS FAST there are 3 denominations of bills in a wallet: $1, $5, and $10. there are 5 fewer $5-bills than $1-bill
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The number of $1, $5 and $10 are 49, 44 and 22 respectively.

<h3>How to use equation to find the number of bills?</h3>

There are 3 denominations of bills in a wallet: $1, $5, and $10.

There are 5 fewer $5-bills than $1-bills.

let

x = number of $1 bills

Hence,

number of $5 bills = x - 5

There are half as many $10-bills as $5-bills.

number of $10 bills = 1 / 2 (x - 5)

Therefore,

x + x - 5 + 1 / 2 (x - 5) = 115

2x - 5  + 1 / 2 x - 5 / 2 = 115

2x + 1 / 2 x - 5 - 5 / 2 = 115

5 / 2 x  - 7.5 = 115

2.5x  = 115 + 7.5

x = 122.5 / 2.5

x = 49

Number of $1 bills = 49

Number of $5 bills = 49 - 5 = 44

Number of $10 bills = 1 / 2 (49 - 5) = 22

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