Answer:
5(d - 2) = 45
Step-by-step explanation:
Solve the given equation for d
3(d + 1) = 4(d - 2) ← distribute parenthesis on both sides
3d + 3 = 4d - 8 ( subtract 3d from both sides )
3 = d - 8 ( add 8 to both sides )
11 = d
Then
5(d - 2) = 5(11 - 2) = 5(9) = 45
GuuUuuuuUuuurl we can’t see graphs sos
Step-by-step explanation:
7.5 cups of raisins, 10 cups of peanuts and 5 cups of chocolate chips.
Step-by-step explanation:
We are given that,
The amount of ingredients needed for the trail mix are,
Raisins = \frac{3}{4}
4
3
cup
Peanuts = 1 cup
Chocolate chips = \frac{1}{2}
2
1
cup
Since, Kiran needs to make 10 cups of the trail mix.
The amount of ingredients needed will be,
Raisins = \frac{3}{4}\times 10
4
3
×10 = \frac{30}{4}
4
30
= 7.5 cups
Peanuts = 1 × 10 = 10 cups
Chocolate chips = \frac{1}{2}\times 10
2
1
×10 = 5 cups
Hence, the ingredients needed are 7.5 cups of raisins, 10 cups of peanuts and 5 cups of chocolate chips.
Answer: B, E
Step-by-step explanation:
Check the picture below.
![\stackrel{\textit{\Large Areas}}{\stackrel{triangle}{\cfrac{1}{2}(6)(6)}~~ + ~~\stackrel{semi-circle}{\cfrac{1}{2}\pi (3)^2}}\implies \boxed{18+4.5\pi} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{pythagorean~theorem}{CA^2 = AB^2 + BC^2\implies} CA=\sqrt{AB^2 + BC^2} \\\\\\ CA=\sqrt{6^2+6^2}\implies CA=\sqrt{6^2(1+1)}\implies CA=6\sqrt{2} \\\\\\ \stackrel{\textit{\Large Perimeters}}{\stackrel{triangle}{(6+6\sqrt{2})}~~ + ~~\stackrel{semi-circle}{\cfrac{1}{2}2\pi (3)}}\implies \boxed{6+6\sqrt{2}+3\pi}](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7B%5CLarge%20Areas%7D%7D%7B%5Cstackrel%7Btriangle%7D%7B%5Ccfrac%7B1%7D%7B2%7D%286%29%286%29%7D~~%20%2B%20~~%5Cstackrel%7Bsemi-circle%7D%7B%5Ccfrac%7B1%7D%7B2%7D%5Cpi%20%283%29%5E2%7D%7D%5Cimplies%20%5Cboxed%7B18%2B4.5%5Cpi%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7Bpythagorean~theorem%7D%7BCA%5E2%20%3D%20AB%5E2%20%2B%20BC%5E2%5Cimplies%7D%20CA%3D%5Csqrt%7BAB%5E2%20%2B%20BC%5E2%7D%20%5C%5C%5C%5C%5C%5C%20CA%3D%5Csqrt%7B6%5E2%2B6%5E2%7D%5Cimplies%20CA%3D%5Csqrt%7B6%5E2%281%2B1%29%7D%5Cimplies%20CA%3D6%5Csqrt%7B2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B%5CLarge%20Perimeters%7D%7D%7B%5Cstackrel%7Btriangle%7D%7B%286%2B6%5Csqrt%7B2%7D%29%7D~~%20%2B%20~~%5Cstackrel%7Bsemi-circle%7D%7B%5Ccfrac%7B1%7D%7B2%7D2%5Cpi%20%283%29%7D%7D%5Cimplies%20%5Cboxed%7B6%2B6%5Csqrt%7B2%7D%2B3%5Cpi%7D)
notice that for the perimeter we didn't include the segment BC, because the perimeter of a figure is simply the outer borders.
