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Dennis_Churaev [7]
3 years ago
8

Consider the following pair of equations:

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0
X-1=3x+3----plug the second equation in for x
-4=2x-------get the x on one side by subtracting x and 3
x=-2------divide by 2
y=x-1
y=-3------plug in x

(-2,-3)
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PLEASE HELP ME WITH THIS! ASAP please and thank you
galben [10]

Just plug in

4a / (2b - c)

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5 0
2 years ago
Read 2 more answers
3x to the power of 3 + 21x squared + 36x = 0 by factoring the quadratic equation.
Diano4ka-milaya [45]

Answer:

x = 0, -4 and -3.

Step-by-step explanation:

The given expression is "3x to the power of 3 + 21x squared + 36x = 0".

We can write this expression as follows :

3x^3+21x^2+36x=0

Taking 3x common.

3x(x^2+7x+12)=0\\\\3x=0\ \text{and}\ (x^2+7x+12)=0

x = 3

x^2+7x+12=0\\\\x^2+3x+4x+12=0\\\\x(x+3)+4(x+3)=0\\\\(x+4)(x+3)=0\\\\x=-4,-3

Hence, the solution of the given quadratic equation are x = 0, -4 and -3.

5 0
3 years ago
Madison made the following table to record the height of each person in her family.
alexira [117]
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2 years ago
How can you get equation b from equation A. 3(x+2)=18 B. X+2=18
Rzqust [24]

Answer:

We start with the equation:

A: 3*(x + 2) = 18

And we want to construct equation B:

B: X + 2 = 18

where I suppose that X is different than x.

Because in both equations the right side is the same thing, then the left side also should be the same thing, this means that:

3*(x + 2) = X + 2

Now we can isolate the variable x.

(x + 2) = (X + 2)/3

x = (X + 2)/3 - 2

Then we need to replace x by  (X + 2)/3 - 2 in equation A, and we will get equation B.

Let's do it:

A: 3*(x + 2) = 18

Now we can replace x by =  (X + 2)/3 - 2

3*( (X + 2)/3 - 2 + 2) = 18

3*(  (X + 2)/3 ) = 18

3*(X + 2)/3 = 18

(X + 2) = 18

Which is equation B.

3 0
2 years ago
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