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Softa [21]
3 years ago
13

Rectangle ABCD is congruent to rectangle HGJK

Mathematics
2 answers:
lidiya [134]3 years ago
7 0

Answer:

The area of rectangle ABCD is 198 square inches.

Step-by-step explanation:

It is given that rectangle ABCD is congruent to rectangle HGJK.

The corresponding parts of congruent figure are congruent.

AD\cong HK                        (CPCTC)

AD=HK=18                            (Property of congruent)

In rectangle ABCD the length of the rectangle is 11 inches and width of the rectangle is 18 inches.

The area of a rectangle is

A=length\times width

The area of rectangle ABCD is

A=AB\times AD

A=11\times 18

A=198

Therefore the area of rectangle ABCD is 198 square inches.

Alexxx [7]3 years ago
5 0

Answer: 198 in.²

Step-by-step explanation:

If two shapes are congruent they have the same shape and size.

A = L x W

18 x 11 = 198

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Answer:

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Step-by-step explanation:

I am assuming you only mean the small triangles, not the composite ones.

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Kite E F G H is inscribed in a rectangle. Points F and H are midpoints of sides of the rectangle, and creates a side length of x
Hoochie [10]

Answer:

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Step-by-step explanation:

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lina2011 [118]
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\textsf{Hey there!}

\text{Select the expressions that are equicalent to 8(6m)}\downarrow

\text{We DON'T have any like terms so we CAN'T pair them off!}

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