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Softa [21]
3 years ago
13

Rectangle ABCD is congruent to rectangle HGJK

Mathematics
2 answers:
lidiya [134]3 years ago
7 0

Answer:

The area of rectangle ABCD is 198 square inches.

Step-by-step explanation:

It is given that rectangle ABCD is congruent to rectangle HGJK.

The corresponding parts of congruent figure are congruent.

AD\cong HK                        (CPCTC)

AD=HK=18                            (Property of congruent)

In rectangle ABCD the length of the rectangle is 11 inches and width of the rectangle is 18 inches.

The area of a rectangle is

A=length\times width

The area of rectangle ABCD is

A=AB\times AD

A=11\times 18

A=198

Therefore the area of rectangle ABCD is 198 square inches.

Alexxx [7]3 years ago
5 0

Answer: 198 in.²

Step-by-step explanation:

If two shapes are congruent they have the same shape and size.

A = L x W

18 x 11 = 198

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<h3>What is a rectangle?</h3>

A rectangle is four sided plane figure which each pair of sides equal and opposite to each other. The sides intersect at an angle of 90 degrees.

<u>Given data</u>

Area of the rectangle = 46 square inches

length L = 4 * width W

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Read more on areas of rectangles here: brainly.com/question/2607596

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