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3 years ago

Rectangle ABCD is congruent to rectangle HGJK

Mathematics

2 answers:

lidiya [134]3 years ago

7 0

Answer:

The area of rectangle ABCD is 198 square inches.

Step-by-step explanation:

It is given that rectangle ABCD is congruent to rectangle HGJK.

The corresponding parts of congruent figure are congruent.

$AD\cong HK$ (CPCTC)

$AD=HK=18$ (Property of congruent)

In rectangle ABCD the length of the rectangle is 11 inches and width of the rectangle is 18 inches.

The area of a rectangle is

$A=length\times width$

The area of rectangle ABCD is

$A=AB\times AD$

$A=11\times 18$

$A=198$

Therefore the area of rectangle ABCD is 198 square inches.

Alexxx [7]3 years ago

5 0

Answer: 198 in.²

Step-by-step explanation:

If two shapes are congruent they have the same shape and size.

A = L x W

18 x 11 = 198

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2 years ago

Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3

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3 years ago

Charles biked 2/3 of a kilometer yesterday he biked 7 times as far today how many kilometers did Charles bike today

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Hello!

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4 years ago

Read 2 more answers

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Dafna1 [17]

Answer:

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Step-by-step explanation:

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