Answer:
Step-by-step explanation:
A possible word problem for 3x+10 ≤75 could be
Mat has $75 dollars saved in his wallet and wants to use it for go carts. Knowing that the entrance to the park is $10, and each time around the go cart course is $3 what is the maximum times he can go around?
3x+10 ≤ 75, subtract 10 from both sides
3x ≤ 75-10, divide both sides by 3
x ≤ 65/3
or x ≤ 21.(6)
So it can go around 21 times the most.
Answer:
5
Step-by-step explanation:
In order to solve this problem, we need to use Pythagorem Theorem (a^2+b^2=c^2)
When using the pythagorem theorem the hypoteneuse would be the c^2 and the two other sides would be a and b (the order doesn't matter).
So, our formula would be:
4^2+3^2=c^2
Simplifies into:
25=c^2
In order to remove the exponent 2, we would have to square root both sides by 2. After doing so, you get the answer 5.
Hope this helps! :)
Answer:
320
Step-by-step explanation:
