15. x ≤ -24
x + 19 ≤ -5
x ≤ -24
16. z > -12
3z > -36
z > -12
17. 185 + c > 410; c > 225
18. C.
x - 6 ≥ 1
x ≥ 7
Answer:
The dimension of the play area written algebraically is y²/2 + 9y
Step-by-step explanation:
Let the be x and the width be y
If the length is to be 9 feet longer than half the width,
hence y/2 + 9 = x
hence dimension of the area = (y/2 + 9) × y = y²/2 + 9y
10% = 5
80% = 40
2% = 1
82% = 41
41