Answer:
-2
Step-by-step explanation:
Length x width = area
<span>but
1feet=12</span><span>inches
</span>8 x 12=96
10<span>x96=960</span>
Answer: x = -14/5
Step-by-step explanation: We shall begin by expanding the brackets for both sides of the equation
-2/3 (x + 2) = 1/6 (x + 6)
(-2x/3) -4/3 = (x/6) + 1
By collecting like terms we now have
(-2x/3) - (x/6) = 1 + 4/3
(-4x - x)/6 = 7/3
-5x/6 = 7/3
By cross multiplication we now have
-5x (3) = 7 (6)
-15x = 42
x = -(42/15) {simplify further by dividing the RHS by 3}
x = -14/5
Therefore x equals, minus fourteen over five (-14/5)
Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s
