Solve x2 + 12x + 6 = 0 using the completing-the-square method.
1 answer:
X^2+12x+6=0 subtract 6 from both sides...
x^2+12x=-6 halve linear coefficient, square it, and add it to both sides...
x^2+12x+36=30 now the left side is a perfect square...
(x+6)^2=30 take square root of both sides...
x+6=30^(1/2) subtract 6 from both sides...
x=-6-30^(1/2) and -6+30^(1/2)
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