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Cloud [144]
4 years ago
13

Determine if this series converges or diverges. Find the sum if possible. 250, 50, 10...

Mathematics
2 answers:
Kruka [31]4 years ago
7 0

Answer:

50

Step-by-step explanation:

Elodia [21]4 years ago
3 0

Answer:

312.5

Step-by-step explanation:

We have the series: 250, 50, 10...

As we can see, each subsequent term gets smaller and smaller. Eventually, it will be infinitesimally small. So, our series converges.

We can also see this from our common ratio. Each term is 1/5 of the previous term. Since our r 1/5 is less than 1, our series will converge.

Since it converges, we can indeed find our sum. First, we can write our series using summation. This will be:

\displaystyle{\sum_{n=0}^{\infty} 250(\frac{1}{5})^n }

We can use the following infinite geometric series formula:

\displaystyle{\sum_{n=0}^{\infty} ar^n=\frac{a}{1-r}

So, let's substitute 250 for a and 1/5 for r. This yields:

\displaystyle{\sum_{n=0}^{\infty} 250(\frac{1}{5})^n }=\frac{250}{1-\frac{1}{5}}

Subtract:

\displaystyle{\sum_{n=0}^{\infty} 250(\frac{1}{5})^n }=\frac{250}{\frac{4}{5}}

Divide. So, our series converges to:

\displaystyle{\sum_{n=0}^{\infty} 250(\frac{1}{5})^n }=312.5

And we're done!

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Answer:

x=-7

Step-by-step explanation:

add 4 to both sides. leaving you with x=-7

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1

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The sum of the angle measures in a 21-gon is
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180

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A tailor uses
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Answer:

2.5 yards

Step-by-step explanation:

75÷30=2.5 yards

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2 years ago
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On a morning of a day when the sun will pass directly​ overhead, the shadow of a 60​-ft building on level ground is 25 ft long.
AysviL [449]

Answer:

The shadow is decreasing at the rate of 3.55 inch/min

Step-by-step explanation:

The height of the building = 60ft

The shadow of the building on the level ground is 25ft long

Ѳ is increasing at the rate of 0.24°/min

Using SOHCAHTOA,

Tan Ѳ = opposite/ adjacent

= height of the building / length of the shadow

Tan Ѳ = h/x

X= h/tan Ѳ

Recall that tan Ѳ = sin Ѳ/cos Ѳ

X= h/x (sin Ѳ/cos Ѳ)

Differentiate with respect to t

dx/dt = (-h/sin²Ѳ)dѲ/dt

When x= 25ft

tanѲ = h/x

= 60/25

Ѳ= tan^-1(60/25)

= 67.38°

dѲ/dt= 0.24°/min

Convert the height in ft to inches

1 ft = 12 inches

Therefore, 60ft = 60*12

= 720 inches

Convert degree/min to radian/min

1°= 0.0175radian

Therefore, 0.24° = 0.24 * 0.0175

= 0.0042 radian/min

Recall that

dx/dt = (-h/sin²Ѳ)dѲ/dt

= (-720/sin²(67.38))*0.0042

= (-720/0.8521)*0.0042

-3.55 inch/min

Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min

8 0
4 years ago
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