It's false. It's a product so... Derivative of the first TIMES the second PLUS derivative of second TIMES the first.
Derivative of the first (x^3) = 3x^2 Times the second = 3x^2 * e^x
Derivative of the second = e^x (remains unchanged) Times the first = e^x * x^3 So the answer would be (3x^2)(e^x) + (e^x)(x^3) which can be factorised to form x^2·e^x(3 + x)
