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Alika [10]
2 years ago
10

One year, the population of a city was 64,000. Several years later it was 53,120. Find the percent decrease.

Mathematics
1 answer:
ohaa [14]2 years ago
4 0

Answer:

17% i think

Step-by-step explanation:

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What is the range of the function below?
sergij07 [2.7K]

Answer:

C

Step-by-step explanation:

f(x)=72-4x

72-4x=0

4x=72

x=18

f(x)<=18

3 0
3 years ago
HIGHEST COMMON FACTOR OF 102 AND 153 NEED HELP EXPLAIN FOR AN EXTRA 10 POINTS
Lynna [10]

Answer:

The highest common factor for both 102 and 153 is

GCF- 51

Step-by-step explanation:

51*3= 153

51*2=102

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What is 4•(5+3)=4•8=
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Step-by-step explanation:

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The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
The ratio of boys to girls at a daycare is 5 to 4 which of these cannot be the total number of kids at the daycare ?
Andre45 [30]
I believe the answer is D
6 0
3 years ago
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