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nekit [7.7K]
3 years ago
15

Yoko has a rectangular poster that is 15centimeters long and 12 centimeters wide. What is the area of the poster in square meter

s.
Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0

Answer:

44

Step-by-step explanation:

you would add 15+15 and 12+12 because it is rectangular meaning there are 4 sides 2 for the y angle and 2 for the x angle

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Geometry
igomit [66]

If the base is square, and the perimeter is 14.5, that means that each side of the base is 14.5/4=3.625. Since we now know the length and the width, as well as the height which is 16.8, we plug into the formula \frac{lwh}{3}. So, plug in the details \frac{3.625*3.625*16.8}{3} Your answer will be 73.6 cm^3

4 0
2 years ago
Read 2 more answers
Last month Jim drove his car 2,718.3 miles. That brought the car’s total mileage to 87,416. What was the car’s mileage before la
stich3 [128]

To solve this problem you must apply the proccedure shown below:

1. You have that Jim drove the car 2,718.3 miles for a total mileage of 87,416.

2. Then, to calculate the mileage before last month, you only need to substract the total mileage given in the exercise above and the mileage drove last month, as following:

87,416miles-2,718.3miles=84,697.7miles

Therefore, the answer is: 84,697.7 miles.

3 0
3 years ago
Help plzzzz guys, I'll mark you as a brainiest
umka2103 [35]
Diagonally

the top of the closet
8 0
3 years ago
Find the derivative of the inverse function of the original function f(x)=(x+1)^3-5
____ [38]

Answer:

Step-by-step explanation:

let f(x)=y

y=(x+1)^{3} -5\\flip ~x~and~y\\x=(y+1)^{3}-5\\(y+1)^{3}=x+5\\y=(x+5)^{\frac{1}{3} } -1\\or~f^{-1}(x)=(x+5)^{\frac{1}{3} } -1\\(f^{-1})'(x)=\frac{1}{3} (x+5)^{\frac{-2}{3} }

4 0
3 years ago
A warehouse is 55 yards long, 35 yards wide, and 5 yards high. What is the area of the warehouse floor? If the warehouse is fill
amid [387]

Answer:

The area of the warehouse floor is 1925yd²

The volume of the boxes is 4812.5yd³

Step-by-step explanation:

First we have to calculate the area, for this we must multiply the length by the width

a = area

l = long = 55yd

w = width = 35yd

a = l * w

a = 55yd * 35yd

a = 1925yd²

to calculate the volume we have to multiply the area by the height

asks us for the volume for half the height so we have to divide the height by 2

a = area = 1925yd²

h = height = 5yd/2 = 2.5yd

v = volume

v = a * h

v = 1925yd² * 2.5yd

v = 4812.5yd³

The area of the warehouse floor is 1925yd²

The volume of the boxes is 4812.5yd³

5 0
3 years ago
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