All categories

3 years ago

I need help on my hole homework plzz

Mathematics

2 answers:

irinina [24]3 years ago

8 0

1. 0.2 2. 0.75 3. 0.44 4. 0.95 5. 0.46

6. No 7. No 8. Yes 9. Yes 10. Yes 11. 3/10 / 0.3 12. B

alexgriva [62]3 years ago

3 0

1. 0.2
2. 0.75
3. 0.44
4. 0.95
5. 0.46
6. not equal
7. not equal
8. equal
9. 0.22
10. yes because 2/5 is equal to 0.4
11. 6/20 in simplest form is 3/10 and 6/20 as a decimal is 0.3
12. B.0.25
13. gina is correct because 4/5 is equal to 0.80 and 0.80 is greater than 0.75
14. i divided 4 by 16 and i got 0.25 and 0.25 is equal to 0.25

You might be interested in

Graph the line of the given equation

Dafna11 [192]

Answer:

Step-by-step explanation:

See the attached image

3 0

1 year ago

If sin theta =0.3090, what is the approximate value of csc theta

Eva8 [605]

Answer:

If sine theta = .3090 then arc sine theta =

18 degrees

Then we look up csc 18 degrees which = 3.2361

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Choose all answers that apply. thanks ♡♡

Firlakuza [10]

Answer:

the first one and the second one not the third one

3 0

3 years ago

Read 2 more answers

Use Stokes' Theorem to calculate the circulation of the field F around the curve C in the indicated direction. F = 3yi + yj+zk

jok3333 [9.3K]

Answer:

$\int \int \bigtriangledown F\ X\ dS = \int F\cdot dr$ = 12π

Step-by-step explanation:

The field F is given by:

$F = 3y\hat{i} + y\hat{j}+z\hat{k}$ (1)

The curve C is the ellipse:

$\frac{x^2}{4}+\frac{y^2}{64}=1\\\\(\frac{x}{2})^2+(\frac{y}{8})^2=1$

In order to calculate the circulation of F around the curve C, you first find the parametric equation for the given ellipse.

The general form of an ellipse equation is:

$(\frac{x}{a})^2+(\frac{y}{b})^2=1$

The parametric equation is:

$r(t)=acost \hat{i} + bsint\hat{j}=2cost\hat{i}+8sint\hat{j}$ (2)

The Stokes's theorem is given by the following identity:

$\int \int \bigtriangledown F\ X\ dS = \int F\cdot dr$

The path integral is also:

$\int F\cdot dr=\int F(r(t))\cdot dr(t)$ (3)

For F(r(t)) and dr(t) you obtain:

$F(r(t))=3(8sint)\hat{j}+(8sint)\hat{j}+(z)\hat{k}\\\\dr(t)=(-2sint\hat{i}+8cost\hat{j}+0\hat{k})dt\\\\F(r(t))\cdot dr(t)=(-48sin^2t+64cos^2t)dt$

Next, in the equation (3) you obtain:

$\int_0^{2\pi} (-48sin^2t+64cos^2t)dt=\int_0^{2\pi}(-\frac{48}{2}(1-cos2t)+\frac{64}{2}(1+cos2t))dt\\\\=\int_0^{2\pi}(-24+24cos2t+32+32cos2t)dt\\\\=\int_0^{2\pi}(6+56cos2t)dt\\\\=[6t+56sin2t]_0^{2\pi}=[6(2\pi)-0]=12\pi$

The circulation of the field around C is 12π

5 0

3 years ago

PLEASE HELP I NEED THIS BRAINLISEST AND 20 POINTS

Bingel [31]

Answer:

SA = 18.2+10.4h

59.8yd²

Step-by-step explanation:

Surface area of a 3D shape is the sum of the areas of its faces. A rectangular prism is made of 2 rectangles that make the top and bottom, plus four equal, larger rectangles.

surface area = 2(small rectangles)+4(large rectangles)

surface area = 2(3.5*2.6)+4(2.6h)

SA = 18.2+10.4h

SA = 18.2+10.4(4)

SA = 18.2+41.6

SA = 59.8yd²

3 0

3 years ago