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Alchen [17]
3 years ago
14

How many kilometers are in 5000 cm​

Mathematics
1 answer:
zheka24 [161]3 years ago
7 0

Answer:0.05 kilometers are in 5000cm

Step-by-step explanation:

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There are 7 oak trees in Aidan's yard. The other 2 trees in his yard are maple trees.
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7/9 of his trees are oak trees

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The sum of 55+66 as the product of their gcf and another sum
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55+66=121 \\\\ 55|5 \\11|11 \\1 \\\\ 55=5*11 \\\\ 66|6\\11|11\\1 \\\\66=6*11 \\\\ G.C.F(55;66)=11 \\\\ 11*x=121 \\\\ x=3+8 \\\\ \boxed{11*(3+8)=121}
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3 years ago
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Write a 3-digit number that is divisible by both 3 and 4. Explain how you know this number is divisible by 3 and 4.
Alexeev081 [22]

Answer:

let us assume the 3 digit number be 984

To check weather the number is divisible by 3 and 4 then when should know the divisibility rule of 3 and 4.

A number is said to be divisible by 3 when the sum of each digit of the number is divisible by 3. Example 9+8+4 = 21 is divisible by 3 hence the number is divisible by 3.

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3 years ago
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Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

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(-2)2+3= -1 hope this helps you
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